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7. (a) A system of linear equations with fewer equations than unknowns is often underdetermined system. Suppose that such a system is consistent. Ext it must have an infinite number of solutions. (b) A system of linear equations with more equations than unknowns is off a overdetermined system. Can such a system be consistent? Give an exa system with three equations in two unknowns to illustrate your answer. 8. A system of linear equations is called homogeneous if the right hand side of e

Ask by Cummings Reeves. in South Africa
Feb 22,2025

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**Problem 7:** **(a)** An underdetermined system with fewer equations than unknowns and that is consistent must have an infinite number of solutions. **(b)** An overdetermined system with more equations than unknowns can be consistent. For example, consider: 1. \(x + y = 2\) 2. \(2x + 2y = 4\) 3. \(3x + 3y = 6\) This system is consistent and has infinitely many solutions along the line \(x + y = 2\). **Problem 8:** A homogeneous system of linear equations is one where all equations equal zero. Such systems always have at least one solution (the trivial solution where all variables are zero). If there are more unknowns than equations, there are infinitely many solutions.

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Let's break down the problems step by step. ### Problem 7 #### (a) Underdetermined System An underdetermined system of linear equations has fewer equations than unknowns. If such a system is consistent, it means that there is at least one solution. However, because there are more unknowns than equations, there are not enough constraints to uniquely determine all the unknowns. Therefore, this system must have an infinite number of solutions. **Conclusion for (a):** Yes, if a consistent underdetermined system has fewer equations than unknowns, it must have an infinite number of solutions. #### (b) Overdetermined System An overdetermined system of linear equations has more equations than unknowns. Such a system can be consistent if all the equations do not contradict each other. However, it is also possible for an overdetermined system to be inconsistent if the additional equations introduce contradictions. **Example of a consistent overdetermined system:** Consider the following system of three equations in two unknowns \(x\) and \(y\): 1. \(x + y = 2\) 2. \(2x + 2y = 4\) 3. \(3x + 3y = 6\) In this case, all three equations represent the same line in the \(xy\)-plane. Therefore, they are consistent, and the system has infinitely many solutions along the line defined by \(x + y = 2\). **Conclusion for (b):** Yes, an overdetermined system can be consistent. The example provided illustrates this. ### Problem 8 A system of linear equations is called homogeneous if the right-hand side of each equation is equal to zero. In other words, a homogeneous system can be expressed in the form: \[ A\mathbf{x} = \mathbf{0} \] where \(A\) is a matrix of coefficients, \(\mathbf{x}\) is a vector of unknowns, and \(\mathbf{0}\) is the zero vector. Homogeneous systems always have at least one solution, which is the trivial solution where all unknowns are zero. If the system has more unknowns than equations, it will also have infinitely many solutions. If you have any further questions or need additional examples, feel free to ask!

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In an underdetermined system, where there are fewer equations than unknowns and it’s consistent, the presence of free variables allows for multiple solutions. Think of it as a spaghetti junction: with fewer roads (equations) than destinations (unknowns), you have many paths to choose from, leading to infinite possible solutions, each uniquely tied to the values assigned to those free variables! For overdetermined systems, consistency is possible but not guaranteed. An example of this is the equations: 1. \( x + y = 2 \) 2. \( 2x + 2y = 4 \) 3. \( 3x + 3y = 6 \) Here, we have three equations and two unknowns (x and y). All three equations represent the same line, meaning the system is consistent and has infinitely many solutions along that line. However, if we added another equation like \( x + y = 5 \), then we would have an inconsistency since it contradicts the previous equations!

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