Question
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Dados los polinomios \( P(x)=-7 x^{4}+6 x^{2}+6 x+5 \) \( \mathrm{Q}(x)=-2 x^{2}+2+3 x^{5} \) \( \mathrm{R}(x)=x^{3}-x^{5}+3 x^{2} \) calcula: \( \quad \) a. \( \mathrm{P}(x)+\mathrm{Q}(x) \)

Ask by Boyd Zimmerman. in Colombia
Mar 16,2025

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Tutor-Verified Answer

Answer

\( P(x) + Q(x) = 3x^5 - 7x^4 + 4x^2 + 6x + 7 \)

Solution

1. Escribimos los polinomios dados: \[ P(x)=-7x^4+6x^2+6x+5 \] \[ Q(x)=3x^5-2x^2+2 \] 2. Para hallar \(P(x)+Q(x)\), sumamos los términos semejantes de ambos polinomios, ordenando los términos de mayor a menor grado: - Término de grado 5: Solo aparece en \(Q(x)\): \(3x^5\). - Término de grado 4: Solo aparece en \(P(x)\): \(-7x^4\). - Término de grado 2: En \(P(x)\) tenemos \(6x^2\) y en \(Q(x)\) \(-2x^2\). Sumamos: \[ 6x^2-2x^2=4x^2 \] - Término de grado 1: Solo aparece en \(P(x)\): \(6x\). - Término independiente: En \(P(x)\) es \(5\) y en \(Q(x)\) es \(2\). Sumamos: \[ 5+2=7 \] 3. Por lo tanto, la suma es: \[ P(x)+Q(x)=3x^5-7x^4+4x^2+6x+7 \]

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Para calcular \( P(x) + Q(x) \), simplemente sumamos los términos similares de ambos polinomios. Empezamos con \( P(x) = -7x^4 + 6x^2 + 6x + 5 \) y \( Q(x) = 3x^5 - 2x^2 + 3x + 2 \). Sumamos: \[ P(x) + Q(x) = (-7x^4) + (3x^5) + (6x^2 - 2x^2) + (6x + 3x) + 5 + 2 \] Esto se simplifica a: \[ = 3x^5 - 7x^4 + 4x^2 + 9x + 7 \] Por lo tanto, \[ P(x) + Q(x) = 3x^5 - 7x^4 + 4x^2 + 9x + 7 \]

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