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\( h(z) = -\frac{2}{25} \)
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Bonus Knowledge
To solve for \( h(z) \), we first simplify the expression given: \[ h(z) = -2 \cdot 5^{-1-1} = -2 \cdot 5^{-2}. \] Now, recall that \( 5^{-2} \) is equivalent to \( \frac{1}{5^2} \), which is \( \frac{1}{25} \). Therefore, substituting this into the equation gives: \[ h(z) = -2 \cdot \frac{1}{25} = -\frac{2}{25}. \] So the final value of \( h(z) \) is: \[ h(z) = -\frac{2}{25}. \]