Question
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If the current dividend \( \left(\mathrm{D}^{0}\right) \) is \( \$ 3.00 \) and the growth rate is \( 6 \% \). How much will the dividend be, at Time 5 ?

Ask by Davies Carroll. in the United States
Mar 10,2025

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Tutor-Verified Answer

Answer

The dividend at Time 5 will be approximately \$4.01.

Solution

To find the dividend at Time 5, we can use the formula for compound interest: \[ A = P \times (1 + r)^n \] where: - \( A \) is the amount at Time 5, - \( P \) is the initial dividend (\( \$3.00 \)), - \( r \) is the growth rate (\( 6\% \)), - \( n \) is the number of years (5 years). Given: - Initial dividend (\( P \)) = \( \$3.00 \) - Growth rate (\( r \)) = \( 6\% \) = \( 0.06 \) - Time (5 years) Substitute the values into the formula: \[ A = 3.00 \times (1 + 0.06)^5 \] Now, we can calculate the dividend at Time 5. Calculate the value by following steps: - step0: Calculate: \(3\left(1+0.06\right)^{5}\) - step1: Add the numbers: \(3\times 1.06^{5}\) - step2: Convert the expressions: \(3\left(\frac{53}{50}\right)^{5}\) - step3: Simplify: \(3\times \frac{53^{5}}{50^{5}}\) - step4: Multiply: \(\frac{3\times 53^{5}}{50^{5}}\) The dividend at Time 5 will be approximately $4.01.

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Extra Insights

To find the future dividend at Time 5, we can use the formula for calculating future dividends with constant growth: \[ \mathrm{D}^{t} = \mathrm{D}^{0} \times (1 + g)^t \] where \( \mathrm{D}^{0} \) is the current dividend, \( g \) is the growth rate, and \( t \) is the time in years. Plugging in the numbers: \[ \mathrm{D}^{5} = 3.00 \times (1 + 0.06)^5 \] Calculating it out: \[ \mathrm{D}^{5} = 3.00 \times (1.338225) \approx 4.014675 \] So, the dividend at Time 5 will be approximately \( \$ 4.01 \). Feel free to ask if you'd like to dive deeper into dividend growth models or explore other finance-related queries!

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