Question
EXERCISE 6.3 For each of the following sequences, determine the general rule and hence the \( 100^{\text {th }} \) term \( \begin{array}{lll}\text { (a) } 1 ; 4 ; 9 ; 16 ; \ldots & \text { (b) } 2 ; 5 ; 10 ; 17 ; \ldots & \text { (c) } 4 ; 7 ; 12 ; 19 ; \ldots \\ \text { (d) } 5 ; 8 ; 13 ; 20 ; \ldots & \text { (e) } 0 ; 3 ; 8 ; 15 ; \ldots & \text { (f) }-1 ; 2 ; 7 ; 14 ; \ldots \\ \text { (g) } 2 ; 8 ; 18 ; 32 ; \ldots & \text { (h) } 3 ; 12 ; 27 ; 48 ; \ldots & \text { (i)* } 4 ; 9 ; 16 ; 25 ; \ldots \\ \text { (j)* } 0 ; 1 ; 4 ; 9 ; \ldots & \text { (k)* } \frac{1}{2} ; 2 ; \frac{9}{2} ; 8 ; \ldots & \text { (l)* } \frac{1}{4} ; 1 ; \frac{9}{4} ; 4 ; \ldots\end{array} \)
Ask by Harper Rose. in South Africa
Mar 06,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
Here are the general rules and the \( 100^{\text{th}} \) terms for each sequence:
**(a)**
*General Rule:* \( a_n = n^2 \)
*100th Term:* 10,000
**(b)**
*General Rule:* \( a_n = n^2 + n \)
*100th Term:* 10,100
**(c)**
*General Rule:* \( a_n = n^2 + 3 \)
*100th Term:* 10,003
**(d)**
*General Rule:* \( a_n = n^2 + 4 \)
*100th Term:* 10,004
**(e)**
*General Rule:* \( a_n = n^2 - 1 \)
*100th Term:* 9,999
**(f)**
*General Rule:* \( a_n = n^2 - 1 \)
*100th Term:* 9,999
**(g)**
*General Rule:* \( a_n = 2n^2 \)
*100th Term:* 20,000
**(h)**
*General Rule:* \( a_n = n^3 - n \)
*100th Term:* 999,900
**(i)**
*General Rule:* \( a_n = (n + 1)^2 \)
*100th Term:* 10,201
**(j)**
*General Rule:* \( a_n = n^2 \)
*100th Term:* 10,000
**(k)**
*General Rule:* \( a_n = \frac{n^2 + n}{2} \)
*100th Term:* 5,050
Solution
To determine the general rule for each sequence and find the \( 100^{\text{th}} \) term, we will analyze each sequence step by step.
### (a) Sequence: \( 1, 4, 9, 16, \ldots \)
This sequence consists of perfect squares:
- \( 1 = 1^2 \)
- \( 4 = 2^2 \)
- \( 9 = 3^2 \)
- \( 16 = 4^2 \)
**General Rule:** \( a_n = n^2 \)
**100th Term:**
\[
a_{100} = 100^2 = 10000
\]
### (b) Sequence: \( 2, 5, 10, 17, \ldots \)
The differences between terms are:
- \( 5 - 2 = 3 \)
- \( 10 - 5 = 5 \)
- \( 17 - 10 = 7 \)
The differences \( 3, 5, 7 \) increase by \( 2 \) each time, indicating a quadratic sequence.
**General Rule:** \( a_n = n^2 + n \)
**100th Term:**
\[
a_{100} = 100^2 + 100 = 10000 + 100 = 10100
\]
### (c) Sequence: \( 4, 7, 12, 19, \ldots \)
The differences between terms are:
- \( 7 - 4 = 3 \)
- \( 12 - 7 = 5 \)
- \( 19 - 12 = 7 \)
The differences \( 3, 5, 7 \) also increase by \( 2 \).
**General Rule:** \( a_n = n^2 + 3 \)
**100th Term:**
\[
a_{100} = 100^2 + 3 = 10000 + 3 = 10003
\]
### (d) Sequence: \( 5, 8, 13, 20, \ldots \)
The differences are:
- \( 8 - 5 = 3 \)
- \( 13 - 8 = 5 \)
- \( 20 - 13 = 7 \)
Again, the differences \( 3, 5, 7 \) increase by \( 2 \).
**General Rule:** \( a_n = n^2 + 4 \)
**100th Term:**
\[
a_{100} = 100^2 + 4 = 10000 + 4 = 10004
\]
### (e) Sequence: \( 0, 3, 8, 15, \ldots \)
The differences are:
- \( 3 - 0 = 3 \)
- \( 8 - 3 = 5 \)
- \( 15 - 8 = 7 \)
The differences \( 3, 5, 7 \) increase by \( 2 \).
**General Rule:** \( a_n = n^2 - 1 \)
**100th Term:**
\[
a_{100} = 100^2 - 1 = 10000 - 1 = 9999
\]
### (f) Sequence: \( -1, 2, 7, 14, \ldots \)
The differences are:
- \( 2 - (-1) = 3 \)
- \( 7 - 2 = 5 \)
- \( 14 - 7 = 7 \)
The differences \( 3, 5, 7 \) increase by \( 2 \).
**General Rule:** \( a_n = n^2 - 1 \)
**100th Term:**
\[
a_{100} = 100^2 - 1 = 10000 - 1 = 9999
\]
### (g) Sequence: \( 2, 8, 18, 32, \ldots \)
The differences are:
- \( 8 - 2 = 6 \)
- \( 18 - 8 = 10 \)
- \( 32 - 18 = 14 \)
The differences \( 6, 10, 14 \) increase by \( 4 \).
**General Rule:** \( a_n = 2n^2 \)
**100th Term:**
\[
a_{100} = 2 \cdot 100^2 = 2 \cdot 10000 = 20000
\]
### (h) Sequence: \( 3, 12, 27, 48, \ldots \)
The differences are:
- \( 12 - 3 = 9 \)
- \( 27 - 12 = 15 \)
- \( 48 - 27 = 21 \)
The differences \( 9, 15, 21 \) increase by \( 6 \).
**General Rule:** \( a_n = n^3 - n \)
**100th Term:**
\[
a_{100} = 100^3 - 100 = 1000000 - 100 = 999900
\]
### (i) Sequence: \( 4, 9, 16, 25, \ldots \)
This sequence consists of perfect squares:
- \( 4 = 2^2 \)
- \( 9 = 3^2 \)
- \( 16 = 4^2 \)
- \( 25 = 5^2 \)
**General Rule:** \( a_n = (n + 1)^2 \)
**100th Term:**
\[
a_{100} = (100 + 1)^2 = 101^2 = 10201
\]
### (j) Sequence: \( 0, 1, 4, 9, \ldots \)
This sequence consists of perfect squares:
- \( 0 = 0^2 \)
- \( 1 = 1^2 \)
- \( 4 = 2^2 \)
- \( 9 = 3^2 \)
**General Rule:** \( a_n = n^2 \)
**100th Term:**
\[
a_{100} = 100^2 = 10000
\]
### (k) Sequence: \( \frac{1}{2}, 2, \frac{9}{2}, 8, \ldots \)
The differences are:
- \( 2 - \frac{1}{2} = \frac{3}{2} \)
- \( \frac{9}{2} - 2 = \frac{5}{2} \)
- \( 8 - \frac{9}{2} = \frac{7}{2} \)
The differences \( \frac{3}{2}, \frac{5}{2}, \frac{7}{2} \) increase by \( 1 \).
**General Rule:** \( a_n = \frac{n^2 + n}{2} \)
**100th Term:**
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Beyond the Answer
1. For the sequence \( (a) \) 1, 4, 9, 16, ... the general rule is \( n^2 \) where \( n \) is the term's position in the sequence. So the \( 100^{\text{th}} \) term is \( 100^2 = 10,000 \). 2. In sequence \( (b) \) 2, 5, 10, 17, ..., the pattern involves consecutive squares and can be expressed as \( n^2 + 1 \) for \( n = 1, 2, 3, ...\). Therefore, the \( 100^{\text{th}} \) term would be \( 100^2 + 1 = 10,001 \).