Question
If the actual concentration of \( \mathrm{MgSO}_{4} \) is 1.985 M and we use 10.8 mL of this in the first trial, how many moles of \( \mathrm{MgSO}_{4} \) reacted? (answer to 4 decimal places) Your Answer:
Ask by Sullivan Stephens. in the United States
Feb 20,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
0.0214 moles of MgSO₄ reacted.
Solution
To find the number of moles, use the formula:
moles = molarity × volume (in liters).
First, convert the volume from mL to L:
10.8 mL = 10.8/1000 = 0.0108 L.
Now, calculate the moles:
moles = 1.985 M × 0.0108 L = 0.021438 moles.
Rounded to four decimal places, the number of moles is 0.0214.
Thus, 0.0214 moles of MgSO₄ reacted.
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Simplify this solution Extra Insights
To find the number of moles of \( \mathrm{MgSO}_{4} \) that reacted, we use the formula: \[ \text{Moles} = \text{Concentration (M)} \times \text{Volume (L)} \] First, convert the volume from mL to L: \[ 10.8 \, \text{mL} = 0.0108 \, \text{L} \] Now, plug in the values: \[ \text{Moles} = 1.985 \, \text{M} \times 0.0108 \, \text{L} = 0.021426 \, \text{mol} \] Rounding to four decimal places, the number of moles of \( \mathrm{MgSO}_{4} \) that reacted is: \[ \text{Your Answer: } 0.0214 \, \text{mol} \]
