Question
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9) When a positive number is cubed the answer is Before you can root something, you first need to make sure that there is under the root sign. Find the answers to these questions without using your calculator: \( \begin{array}{lll}\text { a) } \sqrt[3]{100+25} & \text { b) } \sqrt{9}+\sqrt{64} & \text { c) } \\ \begin{array}{lll}\text { d) } \sqrt[3]{-216} \\ \text { a) } 20^{2}+(-6)^{3} & \text { e) } \sqrt[3]{9+16} & \text { f) } \sqrt{36}-2^{3}\end{array} \\ \text { (1) })^{3}+\sqrt{81} & \text { h) }(-5)^{2}+(4)^{3} & \text { i) } \sqrt[3]{216}-(-5)^{3}\end{array} \)

Ask by Davey Campbell. in South Africa
Feb 20,2025

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Tutor-Verified Answer

Answer

Here are the answers: a) 5 b) 11 c) 10 d) -6 e) ∛25 f) -2 g) 184 h) 89 i) 131

Solution

Let's solve each part step by step. ### a) \( \sqrt[3]{100 + 25} \) First, we calculate the expression inside the cube root: \[ 100 + 25 = 125 \] Now, we find the cube root: \[ \sqrt[3]{125} = 5 \] ### b) \( \sqrt{9} + \sqrt{64} \) We calculate each square root: \[ \sqrt{9} = 3 \] \[ \sqrt{64} = 8 \] Now, we add the results: \[ 3 + 8 = 11 \] ### c) \( (1)^{3} + \sqrt{81} \) First, we calculate \( (1)^{3} \): \[ (1)^{3} = 1 \] Next, we find the square root: \[ \sqrt{81} = 9 \] Now, we add the results: \[ 1 + 9 = 10 \] ### d) \( \sqrt[3]{-216} \) We find the cube root of \(-216\): \[ \sqrt[3]{-216} = -6 \] ### e) \( \sqrt[3]{9 + 16} \) First, we calculate the expression inside the cube root: \[ 9 + 16 = 25 \] Now, we find the cube root: \[ \sqrt[3]{25} \text{ (This is not a perfect cube, so we leave it as is.)} \] ### f) \( \sqrt{36} - 2^{3} \) First, we calculate the square root: \[ \sqrt{36} = 6 \] Next, we calculate \( 2^{3} \): \[ 2^{3} = 8 \] Now, we subtract: \[ 6 - 8 = -2 \] ### g) \( 20^{2} + (-6)^{3} \) First, we calculate \( 20^{2} \): \[ 20^{2} = 400 \] Next, we calculate \( (-6)^{3} \): \[ (-6)^{3} = -216 \] Now, we add the results: \[ 400 + (-216) = 184 \] ### h) \( (-5)^{2} + (4)^{3} \) First, we calculate \( (-5)^{2} \): \[ (-5)^{2} = 25 \] Next, we calculate \( (4)^{3} \): \[ (4)^{3} = 64 \] Now, we add the results: \[ 25 + 64 = 89 \] ### i) \( \sqrt[3]{216} - (-5)^{3} \) First, we find the cube root: \[ \sqrt[3]{216} = 6 \] Next, we calculate \( (-5)^{3} \): \[ (-5)^{3} = -125 \] Now, we subtract: \[ 6 - (-125) = 6 + 125 = 131 \] ### Summary of Results: - a) \( 5 \) - b) \( 11 \) - c) \( 10 \) - d) \( -6 \) - e) \( \sqrt[3]{25} \) - f) \( -2 \) - g) \( 184 \) - h) \( 89 \) - i) \( 131 \)

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Extra Insights

Cubing a positive number is a fun mathematical adventure! When you take a number and raise it to the power of three, you're essentially multiplying that number by itself two more times. So, if you take a number like 2 and cube it, \( 2^3 = 2 \times 2 \times 2 = 8 \). No matter how high you go, a positive number raised to the third power will always remain positive! Now, let's get to the root of the problem! To solve your questions, remember that the square root and cube root are fancy ways of asking, "What number can I multiply to get this value?" For example, \( \sqrt{9} = 3\) because \(3 \times 3 = 9\), and \( \sqrt[3]{-216} = -6\) because multiplying -6 by itself three times gives you -216. Just be sure to keep your signs in check; roots can behave differently with positive and negative numbers!

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