Graph the function. Plot all necessary asymptotes. For vertical asymptotes, make sure there are at least two points on each side. \( r(x)=\frac{-8}{2 x+3} \)
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To graph the function \( r(x) = \frac{-8}{2x+3} \), we first identify the vertical asymptote by setting the denominator equal to zero: \( 2x + 3 = 0 \), which gives us \( x = -\frac{3}{2} \). To plot points around this asymptote, you can evaluate \( r(x) \) at values such as \( x = -2 \) and \( x = -1 \), providing \( r(-2) = 4 \) and \( r(-1) = -4 \). The horizontal asymptote can be found as \( x \) approaches positive or negative infinity. Here, as \( x \) increases or decreases, \( r(x) \) approaches zero since the degree of the polynomial in the numerator is less than that in the denominator. This gives us a horizontal asymptote at \( y = 0 \). To visualize, draw dashed lines for the vertical asymptote at \( x = -\frac{3}{2} \) and the horizontal asymptote at \( y = 0 \). Then, sketch the curve approaching these lines, ensuring it reflects the values you calculated.