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Use a calculator to decide whether the statement is true or false. \[ \sin 64^{\circ}=2 \cos 16^{\circ} \sin 16^{\circ} \] The statement \( \sin 64^{\circ}=2 \cos 16^{\circ} \sin 16^{\circ} \) is \( \square \mathbf{\nabla} \)

Ask by Lawson Delgado. in the United States
Mar 13,2025

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Answer

The statement is false.

Solution

We start by applying the double-angle formula: \[ 2\cos \theta \sin \theta = \sin(2\theta). \] Letting \(\theta = 16^\circ\), we have: \[ 2\cos 16^\circ \sin 16^\circ = \sin(32^\circ). \] Thus, the original statement becomes: \[ \sin 64^\circ = \sin 32^\circ. \] Next, we compare the values: \[ \sin 64^\circ \approx 0.8988, \quad \sin 32^\circ \approx 0.5299. \] Since \(0.8988 \neq 0.5299\), the statement is false. The final answer is: false.

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To evaluate the statement, we'll first calculate both sides using a calculator. The left side is simply \(\sin 64^\circ\). On the right side, we first need to calculate \(\cos 16^\circ\) and \(\sin 16^\circ\), and then use those values to find \(2 \cos 16^\circ \sin 16^\circ\). Calculating \(\sin 64^\circ \approx 0.8988\). Next, calculate: \(\cos 16^\circ \approx 0.9613\) and \(\sin 16^\circ \approx 0.2764\). Now, calculate the right side: \[ 2 \cos 16^\circ \sin 16^\circ \approx 2 \cdot 0.9613 \cdot 0.2764 \approx 0.5314 \]. Now compare both sides: \[ \sin 64^\circ \approx 0.8988 \quad \text{and} \quad 2 \cos 16^\circ \sin 16^\circ \approx 0.5314 \]. Since \(0.8988 \neq 0.5314\), the statement \( \sin 64^\circ=2 \cos 16^\circ \sin 16^\circ \) is **false**.

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