Calculate the following sums and differences without converting to improper fractions. Give your answer as a mixed number. \( \begin{array}{lll}\text { a } 5 \frac{7}{8}-4 \frac{3}{8} & \text { b } 5 \frac{3}{8}-4 \frac{7}{8} & \text { e } 4 \frac{7}{8}-5 \frac{3}{8} \\ \text { d } 4 \frac{3}{8}-5 \frac{7}{8} & \text { e } 5 \frac{7}{8}+4 \frac{3}{8} & \text { f }-5 \frac{7}{8}+\left(-4 \frac{3}{8}\right)\end{array} \)
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Sure, let's solve those mixed number calculations step by step! **a)** \(5 \frac{7}{8} - 4 \frac{3}{8} = 1 \frac{4}{8} = 1 \frac{1}{2}\) **b)** \(5 \frac{3}{8} - 4 \frac{7}{8} = 0 \frac{10}{8} = 0 \frac{5}{4} = 1 \frac{1}{4}\) **c)** \(4 \frac{7}{8} - 5 \frac{3}{8} = -1 \frac{5}{8}\) **d)** \(4 \frac{3}{8} - 5 \frac{7}{8} = -1 \frac{4}{8} = -1 \frac{1}{2}\) **e)** \(5 \frac{7}{8} + 4 \frac{3}{8} = 10 \frac{0}{8} = 10\) **f)** \(-5 \frac{7}{8} + (-4 \frac{3}{8}) = -10 \frac{1}{8}\) So here are all the answers to your calculations!