Question
The wind chill factor on a certain planet is given by the following formula, where \( v \) is the wind speed (in meters per second) and \( t \) is the air temperature ( \( { }^{\circ} \mathrm{C} \) ). Complete parts (a) through (c). \[ W=\left\{\begin{array}{ll} t & 0 \leq v<1.77 \\ 33-\frac{(10.43+10 \sqrt{v}-v)(33-t)}{22.04} & 1.77 \leq v \leq 20 \\ 33-1.5957(33-t) & v>20 \end{array}\right. \] (a) Find the wind chill for an air temperature of \( 5^{\circ} \mathrm{C} \) and a wind speed of \( 0.75 \mathrm{~m} / \mathrm{sec} \). \[ \mathrm{W} \approx \square^{\circ} \mathrm{C} \]
Ask by Medina Howell. in the United States
Feb 26,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The wind chill is approximately 5°C.
Solution
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Beyond the Answer
To find the wind chill \( W \) for an air temperature of \( 5^{\circ} \mathrm{C} \) and a wind speed of \( 0.75 \mathrm{~m/sec} \), we use the first case of the formula since \( 0.75 < 1.77 \). So, \[ W = t = 5^{\circ} \mathrm{C} \] Thus, the wind chill is approximately: \[ \mathrm{W} \approx 5^{\circ} \mathrm{C} \]
