Find the limit. $$ \lim _{x \rightarrow 0} \frac{1}{x^{2 / 3}} $$

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Calculate the limit $$ \lim_{x ightarrow 0} \frac{1}{x^{2/3}} $$.
Evaluate the limit by following steps:
- step0: Evaluate the limit:
  $$\lim _{xightarrow 0}\left(\frac{1}{x^{\frac{2}{3}}}ight)$$
- step1: Evaluate the left-hand and the right-hand limits:
  $$\begin{align}&\lim _{xightarrow 0^{-}}\left(\frac{1}{x^{\frac{2}{3}}}ight)\&\lim _{xightarrow 0^{+}}\left(\frac{1}{x^{\frac{2}{3}}}ight)\end{align}$$
- step2: Evaluate the left-hand limit:
  $$\begin{align}&+\infty\&+\infty\end{align}$$
- step3: Calculate:
  $$+\infty$$
The limit of $$ \frac{1}{x^{2/3}} $$ as $$ x $$ approaches 0 is $$ +\infty $$.
The limit is $$ +\infty $$.

Find the limit. \( \lim _{x \rightarrow 0} \frac{1}{x^{2 / 3}} \)

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