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\begin{tabular}{|l} Determine the number of moles of aluminum in 96.7 g of AI. \\ 4.21 mol \\ 3.58 mol \\ \( 6.02 \times 10^{23} \mathrm{~mol} \) \\ 7.43 mol \\ 0.279 mol\end{tabular}

Ask by Gibbs Turner. in the United States
Feb 25,2025

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Answer

There are approximately 3.58 moles of aluminum in 96.7 grams of Al.

Solution

The number of moles is given by the formula:   moles = mass / molar mass For aluminum (Al), the molar mass is approximately 26.98 g/mol. So we calculate:   moles = 96.7 g / 26.98 g/mol ≈ 3.58 mol Thus, there are approximately 3.58 moles of aluminum in 96.7 g of Al.

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To find the number of moles of aluminum in 96.7 g of Al, we first need to know the molar mass of aluminum, which is approximately 26.98 g/mol. Using the formula: \[ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] we calculate: \[ \text{moles} = \frac{96.7 \, \text{g}}{26.98 \, \text{g/mol}} \approx 3.58 \, \text{mol} \] So the correct answer is approximately 3.58 mol.

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