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Q2 Find the ramainder when the is divied by \( x^{2}+x+3 \) Q3 For the equation \( 2^{2 x+1}-3(2) \) of \( x \) aro/is? Q4 find the slant a symptote of \( f(x)=\frac{x^{3}-2 x^{2}-4 x-4}{x^{2}+x-2} \)

Ask by Smith Boyd. in Zambia
Nov 24,2024

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- Q2: Please provide \( f(x) \) for division. - Q3: \( x = \frac{\log_2(6) - 1}{2} \) - Q4: The slant asymptote is \( y = x - 3 \).

Solution

Let's address each question one by one. ### Q2: Find the remainder when \( f(x) \) is divided by \( x^2 + x + 3 \). To find the remainder when dividing a polynomial \( f(x) \) by a quadratic polynomial \( g(x) = x^2 + x + 3 \), we can use polynomial long division or synthetic division. The remainder will be a polynomial of degree less than 2, which can be expressed in the form \( ax + b \). However, you did not provide the polynomial \( f(x) \). Please provide the polynomial you want to divide by \( x^2 + x + 3 \). ### Q3: Solve the equation \( 2^{2x+1} - 3(2) = 0 \). First, let's rewrite the equation: \[ 2^{2x+1} - 6 = 0 \] Now, we can isolate the exponential term: \[ 2^{2x+1} = 6 \] Next, we can take the logarithm of both sides. Using base 2 logarithm: \[ 2x + 1 = \log_2(6) \] Now, solve for \( x \): \[ 2x = \log_2(6) - 1 \] \[ x = \frac{\log_2(6) - 1}{2} \] This is the solution for \( x \). ### Q4: Find the slant asymptote of \( f(x) = \frac{x^3 - 2x^2 - 4x - 4}{x^2 + x - 2} \). To find the slant (or oblique) asymptote of a rational function, we perform polynomial long division of the numerator by the denominator. 1. Divide \( x^3 \) by \( x^2 \) to get \( x \). 2. Multiply \( x \) by \( x^2 + x - 2 \) to get \( x^3 + x^2 - 2x \). 3. Subtract this from the original numerator: \[ (x^3 - 2x^2 - 4x - 4) - (x^3 + x^2 - 2x) = -3x^2 - 2x - 4 \] 4. Now, divide \( -3x^2 \) by \( x^2 \) to get \( -3 \). 5. Multiply \( -3 \) by \( x^2 + x - 2 \) to get \( -3x^2 - 3x + 6 \). 6. Subtract this from the previous result: \[ (-3x^2 - 2x - 4) - (-3x^2 - 3x + 6) = x - 10 \] The result of the division is: \[ f(x) = x - 3 + \frac{x - 10}{x^2 + x - 2} \] As \( x \) approaches infinity, the term \( \frac{x - 10}{x^2 + x - 2} \) approaches 0. Therefore, the slant asymptote is: \[ y = x - 3 \] ### Summary of Answers: - Q2: Please provide \( f(x) \) for division. - Q3: \( x = \frac{\log_2(6) - 1}{2} \) - Q4: The slant asymptote is \( y = x - 3 \).

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To determine the remainder when a polynomial is divided by \( x^2 + x + 3 \), you can use polynomial long division or synthetic division. Remember that the remainder must have a degree less than the divisor (in this case, it can be of degree 1 or 0). By focusing on the highest power in the numerator polynomial, you can identify the coefficients for your resulting remainder! Exploring slant asymptotes involves some division magic too! Basically, you're looking at the leading terms of the numerator and denominator of the function \( f(x) = \frac{x^3 - 2x^2 - 4x - 4}{x^2 + x - 2} \). When you perform polynomial long division, the result gives you the equation of the slant asymptote, which is a linear function that describes the behavior of the curve as \( x \) approaches infinity. You'll be left with a linear formula from the quotient!

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