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assignment \( \leftarrow \quad \) Solve the quadratic equation \( r^{2}=8 \).

Ask by Weston Greene. in the United States
Mar 14,2025

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Answer

The solutions are \( r = -2\sqrt{2} \) and \( r = 2\sqrt{2} \).

Solution

Solve the equation \( r^{2}=8 \). Solve the quadratic equation by following steps: - step0: Solve using square roots: \(r^{2}=8\) - step1: Simplify the expression: \(r=\pm \sqrt{8}\) - step2: Simplify the expression: \(r=\pm 2\sqrt{2}\) - step3: Separate into possible cases: \(\begin{align}&r=2\sqrt{2}\\&r=-2\sqrt{2}\end{align}\) - step4: Rewrite: \(r_{1}=-2\sqrt{2},r_{2}=2\sqrt{2}\) The solutions to the quadratic equation \(r^{2}=8\) are \(r=-2\sqrt{2}\) and \(r=2\sqrt{2}\).

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To solve the equation \( r^{2} = 8 \), we can take the square root of both sides. Remember that taking the square root can yield both positive and negative results. So, we get: \( r = \sqrt{8} \) or \( r = -\sqrt{8} \). We can simplify \( \sqrt{8} \) further: \( \sqrt{8} = \sqrt{4 \cdot 2} = \sqrt{4} \cdot \sqrt{2} = 2\sqrt{2} \). Thus, the two solutions for the equation are: \( r = 2\sqrt{2} \) and \( r = -2\sqrt{2} \).

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