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Write the trinomial in descending powers of one variable an \[ y^{2}+80+21 y \] SUBMIT ANSWER

Ask by Ryan Greene. in the United States
Mar 10,2025

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Answer

The trinomial in descending powers of \( y \) is \( y^{2} + 21y + 80 \).

Solution

1. The given trinomial is \[ y^{2} + 80 + 21y \] 2. To write it in descending powers of the variable \( y \), we arrange the terms from the highest exponent to the lowest. The term \( y^{2} \) has the highest power, followed by \( 21y \) (which is \( y^1 \)), and finally the constant term \( 80 \). 3. Thus, the trinomial in descending order is \[ y^{2} + 21y + 80 \]

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To write the trinomial in descending powers of one variable, we need to organize the terms starting from the highest power of \( y \) to the constant term. The given expression is: \[ y^2 + 21y + 80 \] Rearranging it in descending order gives us: \[ y^2 + 21y + 80 \] So, the final answer is \( y^2 + 21y + 80 \).

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