(c) Make \( g \) the subject of the formula \( \mathrm{F}=\frac{m v^{2}}{g r} \) (d) Make \( v \) the subject of the formula \( \frac{1}{u}+\frac{1}{v}=\frac{1}{f} \) (a) Make \( c \) the subject of the formula \( \mathrm{E}=m c^{2} \).
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Mind Expander
To isolate \( g \) in the formula \( \mathrm{F}=\frac{m v^{2}}{g r} \), you can rearrange it as follows: multiply both sides by \( g r \) to get \( \mathrm{F}g r = m v^{2} \). Then, divide both sides by \( \mathrm{F} r \) to find \( g = \frac{m v^{2}}{F r} \). For the equation \( \frac{1}{u}+\frac{1}{v}=\frac{1}{f} \), start by finding a common denominator for \( u \) and \( v \). This gives you \( \frac{v + u}{uv} = \frac{1}{f} \). Cross multiplying results in \( (v + u)f = uv \), which simplifies to \( v = \frac{uf}{u - f} \) when isolating \( v \). To express \( c \) as the subject in \( \mathrm{E}=m c^{2} \), simply divide both sides by \( m \): \( \frac{E}{m} = c^{2} \). Finally, take the square root to yield \( c = \sqrt{\frac{E}{m}} \).