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Determine the energy of a photon of electromagnetic radiation with a frequency of 5 MHz .

Ask by Beck Rojas. in South Africa
Feb 25,2025

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Answer

The energy of a photon with a frequency of 5 MHz is approximately 3.31 × 10⁻²⁷ joules.

Solution

The energy E of a photon is given by the equation:   E = h × f where:   h = 6.626 × 10⁻³⁴ joule·seconds (Planck's constant)   f = frequency (in this case, 5 MHz = 5 × 10⁶ Hz) Thus,   E = (6.626 × 10⁻³⁴ J·s) × (5 × 10⁶ Hz)     = 33.13 × 10⁻²⁸ J     = 3.313 × 10⁻²⁷ J So, the energy of a photon with a frequency of 5 MHz is approximately 3.31 × 10⁻²⁷ joules.

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Extra Insights

Did you know that the energy of a photon can be calculated using the simple formula E = h * f, where E is energy, h is Planck's constant (approximately 6.63 x 10^-34 J·s), and f is the frequency in hertz? So for a frequency of 5 MHz (which is 5 x 10^6 Hz), plugging in the numbers gives you an energy of roughly 3.31 x 10^-27 joules. It’s a teeny-tiny amount of energy, perfect for the radio waves used in your favorite music stations! In the grand scheme of things, photons at this frequency are falling into the radio wave part of the electromagnetic spectrum. These waves are crucial in everyday technology, from broadcasting radio signals to communication systems. So, your next conversation with a friend over the radio might just be powered by those diminutive little photons buzzing along at 5 MHz!

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