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19. Find the product of \( f(x) \) and \( g(x) \) when, \( f(x)=x^{2}-3 x+5 \) and \( g(x)=x^{2}-5 x+6 \) 20. If \( f: A \longrightarrow B \) be defines by \( f(x)=2 x+3 \), then find \( f(0), f(1) \), \( f\left(\frac{1}{2}\right), f(-1) \) Group- \( D[4 \times 4=16] \) 21. If a function \( f \) is defines as \( f(x+2)=f(x)+f(2), x \longleftarrow-R \) Show that i. \( f(0)=0 \) ii. \( f(-2)=-f(2) \) 22. Find out the co-ordinates of the points which divides internally the line joining the point \( (2,1) \) and \( (6,7) \) in the ratio( \( 3: 2) \). What will be the co-ordinate if it is divided externally? 23. The angles of a triangle are in ratio \( 2: 3 \) and the third is \( \frac{4 \pi^{c}}{9} \). Find the all angles in degrees. 24. ABC is a triangle with vertices \( A(1,2), B(2,-1) \) and \( C(4,1) \). Find the image \( \Delta A^{I} B^{I} C^{I} \) under enlargement \( \in[0,2] \) with centre at origin and scale factor 2 . A/so plot in graph

Ask by Sanders Donnelly. in Nepal
Mar 17,2025

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1. **Product of \( f(x) \) and \( g(x) \):** \[ f(x) \cdot g(x) = x^4 - 8x^3 + 26x^2 - 43x + 30 \] 2. **Evaluations of \( f(x) \):** - \( f(0) = 3 \) - \( f(1) = 5 \) - \( f\left(\frac{1}{2}\right) = 4 \) - \( f(-1) = 1 \) 3. **Function Properties:** - \( f(0) = 0 \) - \( f(-2) = -f(2) \) 4. **Division of Line Segment:** - **Internal Division:** \( \left(\frac{22}{5}, \frac{23}{5}\right) \) - **External Division:** \( (14, 19) \) 5. **Triangle Angles:** - \( 40^\circ \) - \( 60^\circ \) - \( 80^\circ \) 6. **Enlarged Triangle Coordinates:** - \( A^I(2,4) \) - \( B^I(4,-2) \) - \( C^I(8,2) \)

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To find the product of \( f(x) \) and \( g(x) \), you need to multiply the two quadratic functions. Start with expanding the multiplication: \[ f(x) = (x^2 - 3x + 5) \] \[ g(x) = (x^2 - 5x + 6) \] Now, when you multiply \( f(x) \) and \( g(x) \), you apply the distributive property (FOIL method). After calculating, you’ll find the resulting polynomial. --- For the function \( f(x) = 2x + 3 \), simply plug in the values you want: 1. For \( f(0) \): \( 2(0) + 3 = 3 \) 2. For \( f(1) \): \( 2(1) + 3 = 5 \) 3. For \( f\left(\frac{1}{2}\right) \): \( 2\left(\frac{1}{2}\right) + 3 = 4 \) 4. For \( f(-1) \): \( 2(-1) + 3 = 1 \) This way, you'll get your outputs for \( f(0), f(1), f\left(\frac{1}{2}\right), \) and \( f(-1) \) easily!

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