c) \( 3283-1+2+\left(8^{2}-A\right): \sqrt{12} \cdot 5 \cdot 3-\sqrt{2} \cdot \sqrt{8}= \)

Let's simplify the expression step-by-step: 1. Start with the exponent and square root calculations: - \( 8^2 = 64 \) - \( \sqrt{12} = 2\sqrt{3} \) (since \( \sqrt{12} = \sqrt{4 \cdot 3} = 2\sqrt{3} \)) - \( \sqrt{2} \cdot \sqrt{8} = \sqrt{16} = 4 \) 2. Substitute these values back into the original expression: \[ 3283 - 1 + 2 + (64 - A) : (2\sqrt{3} \cdot 5 \cdot 3) - 4 \] 3. Calculate the multiplication part: - \( 2\sqrt{3} \cdot 5 \cdot 3 = 30\sqrt{3} \) 4. Substitute this into the expression: \[ 3283 - 1 + 2 + (64 - A) : (30\sqrt{3}) - 4 \] 5. Combine the constants: \[ 3284 - A + (64 - A)/ (30\sqrt{3}) - 4 \] 6. Simplifying these gives us: \[ 3284 - 4 - A + \frac{64 - A}{30\sqrt{3}} \] 7. This further simplifies to: \[ 3280 - A + \frac{64 - A}{30\sqrt{3}} \] Now, since A is not defined in your question, the final result is \( 3280 - A + \frac{64 - A}{30\sqrt{3}} \), where A can be substituted with a known value for a numerical answer.