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To solve the equation \( 3 \cdot\left(2^{x}\right)=0.3 \), we first divide both sides by 3 to isolate the exponential term: \( 2^{x} = \frac{0.3}{3} \). Calculating that gives us \( 2^{x} = 0.1 \). Now, to solve for \( x \), we take the logarithm of both sides. Using \( \log_2 \), we find that \( x = \log_2(0.1) \). This can also be expressed using the change of base formula, giving us \( x \approx -3.32 \). For further clarity, you can convert \( 0.1 \) into a fraction, which is \( \frac{1}{10} \). Remembering that \( 10 = 2^{\log_2(10)} \), you can reframe your equation in terms of base-2 logarithms. This can make it easier to visualize the relationship between different bases and help reinforce how logarithms can transform exponential equations into linear ones!