Which is the graph of the linear inequality \( y<3 x+1 \) ?
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To graph the inequality \( y < 3x + 1 \), you start by graphing the line \( y = 3x + 1 \). This line has a slope of 3 and a y-intercept at (0, 1). Use a dashed line to represent the inequality, indicating that points on the line are not included in the solution set. Next, shade the area below the line, representing all the points (x, y) that satisfy the inequality \( y < 3x + 1 \). If you reverse the inequality, for example, to \( y > 3x + 1 \), you would still graph the same line but would shade the area above it instead! Remember, testing points can help you confirm the correct side to shade; for instance, trying (0,0) in the original inequality will show that it does not satisfy.