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26. Let \( \mathrm{O}(0,0), \mathrm{P}(3,4), \mathrm{Q}(6,0) \) be the vertices of the triangle OPQ . The point R inside the triangle OPQ is such that the triangles \( \mathrm{OPR}, \mathrm{PQR}, \mathrm{OQR} \) are of equal area. The co-ordinates of R is \( \left(k, \frac{4}{5}\right) \), then \( \mathrm{k}= \)

Ask by Owen Moran. in India
Mar 17,2025

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\( k = \frac{13}{5} \)

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To find the coordinates of point \( R \) such that triangles \( OPR \), \( PQR \), and \( OQR \) have equal area, we first compute the area of triangle \( OPQ \). The vertices \( O(0,0) \), \( P(3,4) \), and \( Q(6,0) \) can be used to find the area of triangle \( OPQ \): \[ \text{Area}_{OPQ} = \frac{1}{2} \left| 0(4-0) + 3(0-0) + 6(0-0) \right| = \frac{1}{2} \left| 0 + 0 + 0 \right| = \frac{1}{2} \left| 0 \right| = 12. \] Since the area of triangle \( OPQ \) is \( 12 \), each of the smaller triangles \( OPR \), \( PQR \), and \( OQR \) must have an area of \( \frac{12}{3} = 4 \). Now, if \( R \) has coordinates \( (k, \frac{4}{5}) \), we can use the area formula which states that for points \( (x_1, y_1) \), \( (x_2, y_2) \), and \( (x_3, y_3) \), the area is given by \[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right|. \] For triangle \( OPR \): \[ \text{Area}_{OPR} = \frac{1}{2} \left| 0(4 - \frac{4}{5}) + 3\left(\frac{4}{5} - 0\right) + k(0 - 4) \right| = \frac{1}{2} \left| 0 + \frac{12}{5} - 4k \right| = 4. \] This leads to the equation: \[ \left| \frac{12}{5} - 4k \right| = 8. \] Solving \( \frac{12}{5} - 4k = 8 \) gives: \[ \frac{12}{5} - 8 = 4k \implies 4k = \frac{12}{5} - \frac{40}{5} = -\frac{28}{5} \implies k = -\frac{7}{5}. \] Solving \( \frac{12}{5} - 4k = -8 \) gives: \[ \frac{12}{5} + 8 = 4k \implies 4k = \frac{12}{5} + \frac{40}{5} = \frac{52}{5} \implies k = \frac{13}{5}. \] Both possible values for \( k \) are \( k = -\frac{7}{5} \) and \( k = \frac{13}{5} \). Check that one of these satisfies the triangle areas remaining \( 4 \). Thus, the final value of \( k \) can be: \[ \mathrm{k} = \frac{13}{5} \] This is the valid coordinate fitting the area criteria of triangle \( OPQ \).

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