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\begin{tabular}{l} Solve for \( x: \) \\ \( -3 x+6 \leq 2 x+1 \) \\ \hline\end{tabular}

Ask by Wheeler Best. in South Africa
Mar 13,2025

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\( x \geq 1 \)

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Let's solve the inequality step by step! First, we want to rearrange the inequality to isolate \(x\). Start by moving \(2x\) to the left side and \(6\) to the right side: \[ -3x - 2x \leq 1 - 6 \] This simplifies to: \[ -5x \leq -5 \] Next, divide both sides by \(-5\). Remember, when you divide by a negative number, you must flip the inequality sign: \[ x \geq 1 \] So, the solution to the inequality \( -3x + 6 \leq 2x + 1 \) is \( x \geq 1 \).

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