\begin{tabular}{l} Solve for \( x: \) \\ \( -3 x+6 \leq 2 x+1 \) \\ \hline\end{tabular}
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Bonus Knowledge
Let's solve the inequality step by step! First, we want to rearrange the inequality to isolate \(x\). Start by moving \(2x\) to the left side and \(6\) to the right side: \[ -3x - 2x \leq 1 - 6 \] This simplifies to: \[ -5x \leq -5 \] Next, divide both sides by \(-5\). Remember, when you divide by a negative number, you must flip the inequality sign: \[ x \geq 1 \] So, the solution to the inequality \( -3x + 6 \leq 2x + 1 \) is \( x \geq 1 \).
