Question
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g) \( \left(\frac{2}{3}\right)^{2} \div\left(\frac{27}{8}\right)^{-1} \)

Ask by Frank Watson. in Canada
Mar 10,2025

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Tutor-Verified Answer

Answer

The result is \( \frac{3}{2} \) or \( 1\frac{1}{2} \) or \( 1.5 \).

Solution

Calculate or simplify the expression \( (2/3)^2 / (27/8)^(-1) \). Calculate the value by following steps: - step0: Calculate: \(\frac{\left(\frac{2}{3}\right)^{2}}{\left(\frac{27}{8}\right)^{-1}}\) - step1: Multiply by the reciprocal: \(\left(\frac{2}{3}\right)^{2}\times \frac{27}{8}\) - step2: Evaluate the power: \(\frac{2^{2}}{3^{2}}\times \frac{27}{8}\) - step3: Rewrite the expression: \(\frac{2^{2}}{3^{2}}\times \frac{27}{2^{3}}\) - step4: Reduce the numbers: \(\frac{1}{3^{2}}\times \frac{27}{2}\) - step5: Rewrite the expression: \(\frac{1}{3^{2}}\times \frac{3^{3}}{2}\) - step6: Reduce the numbers: \(1\times \frac{3}{2}\) - step7: Multiply: \(\frac{3}{2}\) The result of \( \left(\frac{2}{3}\right)^{2} \div\left(\frac{27}{8}\right)^{-1} \) is \( \frac{3}{2} \) or \( 1\frac{1}{2} \) or \( 1.5 \).

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Mind Expander

To solve \( \left(\frac{2}{3}\right)^{2} \div\left(\frac{27}{8}\right)^{-1} \), we first simplify the expression. Start by calculating \( \left(\frac{2}{3}\right)^{2} \): \[ \left(\frac{2}{3}\right)^{2} = \frac{2^2}{3^2} = \frac{4}{9} \] Next, simplify \( \left(\frac{27}{8}\right)^{-1} \): \[ \left(\frac{27}{8}\right)^{-1} = \frac{8}{27} \] Now, we need to perform the division: \[ \frac{4}{9} \div \frac{8}{27} \] To divide by a fraction, multiply by its reciprocal: \[ \frac{4}{9} \times \frac{27}{8} \] Now, we can simplify before multiplying: 1. \( \frac{4}{8} = \frac{1}{2} \) 2. \( \frac{27}{9} = 3 \) So we have: \[ \frac{1}{2} \times 3 = \frac{3}{2} \] Thus, the final answer is: \[ \frac{3}{2} \]

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