g) \( \left(\frac{2}{3}\right)^{2} \div\left(\frac{27}{8}\right)^{-1} \)
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To solve \( \left(\frac{2}{3}\right)^{2} \div\left(\frac{27}{8}\right)^{-1} \), we first simplify the expression. Start by calculating \( \left(\frac{2}{3}\right)^{2} \): \[ \left(\frac{2}{3}\right)^{2} = \frac{2^2}{3^2} = \frac{4}{9} \] Next, simplify \( \left(\frac{27}{8}\right)^{-1} \): \[ \left(\frac{27}{8}\right)^{-1} = \frac{8}{27} \] Now, we need to perform the division: \[ \frac{4}{9} \div \frac{8}{27} \] To divide by a fraction, multiply by its reciprocal: \[ \frac{4}{9} \times \frac{27}{8} \] Now, we can simplify before multiplying: 1. \( \frac{4}{8} = \frac{1}{2} \) 2. \( \frac{27}{9} = 3 \) So we have: \[ \frac{1}{2} \times 3 = \frac{3}{2} \] Thus, the final answer is: \[ \frac{3}{2} \]
