Given the function \( f \), find \( f(-3), f(2), f(-a),-f(a) \), and \( f(a+h) \). \[ \begin{array}{l} f(x)=\frac{8 x-5}{5 x+4} \\ f(-3)=\square \\ f(2)=\square \\ f(-a)=\square \\ -f(a)=\square \\ f(a+h)=\square\end{array} \]

Evaluate the expression by following steps: - step0: Evaluate: \(\frac{8x-5}{5x+4}\) - step1: Substitute: \(\frac{8\left(-3\right)-5}{5\left(-3\right)+4}\) - step2: Multiply the numbers: \(\frac{-24-5}{5\left(-3\right)+4}\) - step3: Multiply the numbers: \(\frac{-24-5}{-15+4}\) - step4: Subtract the numbers: \(\frac{-29}{-15+4}\) - step5: Add the numbers: \(\frac{-29}{-11}\) - step6: Reduce the fraction: \(\frac{29}{11}\) Substitute \( x=2 \) into the expression \( \frac{8 x-5}{5 x+4} \). Evaluate the expression by following steps: - step0: Evaluate: \(\frac{8x-5}{5x+4}\) - step1: Substitute: \(\frac{8\times 2-5}{5\times 2+4}\) - step2: Multiply the numbers: \(\frac{16-5}{5\times 2+4}\) - step3: Multiply the numbers: \(\frac{16-5}{10+4}\) - step4: Subtract the numbers: \(\frac{11}{10+4}\) - step5: Add the numbers: \(\frac{11}{14}\) Substitute \( x=a+h \) into the expression \( \frac{8 x-5}{5 x+4} \). Evaluate the expression by following steps: - step0: Evaluate: \(\frac{8x-5}{5x+4}\) - step1: Substitute: \(\frac{8\left(a+h\right)-5}{5\left(a+h\right)+4}\) - step2: Expand the expression: \(\frac{8a+8h-5}{5\left(a+h\right)+4}\) - step3: Expand the expression: \(\frac{8a+8h-5}{5a+5h+4}\) Substitute \( x=-a \) into the expression \( \frac{8 x-5}{5 x+4} \). Evaluate the expression by following steps: - step0: Evaluate: \(\frac{8x-5}{5x+4}\) - step1: Substitute: \(\frac{8\left(-a\right)-5}{5\left(-a\right)+4}\) - step2: Multiply the numbers: \(\frac{-8a-5}{5\left(-a\right)+4}\) - step3: Multiply the numbers: \(\frac{-8a-5}{-5a+4}\) - step4: Rewrite the fraction: \(\frac{8a+5}{5a-4}\) Substitute \( x=a \) into the expression \( \frac{8 x-5}{5 x+4} \). Evaluate the expression by following steps: - step0: Evaluate: \(\frac{8x-5}{5x+4}\) - step1: Substitute: \(\frac{8a-5}{5a+4}\) Let's evaluate the function \( f(x) = \frac{8x - 5}{5x + 4} \) for the specified values step by step. 1. **Finding \( f(-3) \)**: \[ f(-3) = \frac{8(-3) - 5}{5(-3) + 4} = \frac{-24 - 5}{-15 + 4} = \frac{-29}{-11} = \frac{29}{11} \] 2. **Finding \( f(2) \)**: \[ f(2) = \frac{8(2) - 5}{5(2) + 4} = \frac{16 - 5}{10 + 4} = \frac{11}{14} \] 3. **Finding \( f(-a) \)**: \[ f(-a) = \frac{8(-a) - 5}{5(-a) + 4} = \frac{-8a - 5}{-5a + 4} = \frac{-8a - 5}{-5a + 4} \] 4. **Finding \( -f(a) \)**: \[ f(a) = \frac{8a - 5}{5a + 4} \implies -f(a) = -\frac{8a - 5}{5a + 4} = \frac{-8a + 5}{5a + 4} \] 5. **Finding \( f(a + h) \)**: \[ f(a + h) = \frac{8(a + h) - 5}{5(a + h) + 4} = \frac{8a + 8h - 5}{5a + 5h + 4} \] Now, we can summarize the results: \[ \begin{array}{l} f(-3) = \frac{29}{11} \\ f(2) = \frac{11}{14} \\ f(-a) = \frac{-8a - 5}{-5a + 4} \\ -f(a) = \frac{-8a + 5}{5a + 4} \\ f(a + h) = \frac{8a + 8h - 5}{5a + 5h + 4} \end{array} \]