Question
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15. Complete the solution of \( |2 x-8|<10 \)

Ask by Pollard Parsons. in the United States
Mar 10,2025

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Tutor-Verified Answer

Answer

The solution is \( -1 < x < 9 \).

Solution

1. Start with the inequality: \[ |2x - 8| < 10 \] 2. Rewrite the inequality without the absolute value by expressing it as a double inequality: \[ -10 < 2x - 8 < 10 \] 3. Add \(8\) to all parts of the inequality: \[ -10 + 8 < 2x - 8 + 8 < 10 + 8 \] which simplifies to: \[ -2 < 2x < 18 \] 4. Divide every part by \(2\) to solve for \(x\): \[ \frac{-2}{2} < \frac{2x}{2} < \frac{18}{2} \] which simplifies to: \[ -1 < x < 9 \] The solution of the inequality is: \[ x \in (-1, 9) \]

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Bonus Knowledge

To solve the inequality \( |2x - 8| < 10 \), we first split it into two separate inequalities based on the definition of absolute value: 1. \( 2x - 8 < 10 \) 2. \( 2x - 8 > -10 \) For the first inequality \( 2x - 8 < 10 \): - Add 8 to both sides: \( 2x < 18 \) - Divide by 2: \( x < 9 \) For the second inequality \( 2x - 8 > -10 \): - Add 8 to both sides: \( 2x > -2 \) - Divide by 2: \( x > -1 \) Combining these results, we get the solution \( -1 < x < 9 \), or in interval notation, \( (-1, 9) \). Remember, the absolute value creates a "sandwich" effect, so you’re essentially looking for values of \( x \) that fall neatly within those bounds!

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