4i) A farmer placed an order for \( \frac{127}{10} \) tons of fertilizer. He calculates that the corn fields will require \( \frac{61}{10} \) tons of it. How much fertilizer will the farmer have left for his other crops? (i) Write your answer as a fraction or as a whole or mixed number.

1. Write the total amount of fertilizer as a fraction: \( \frac{127}{10} \) tons. 2. Write the amount required for the corn fields as a fraction: \( \frac{61}{10} \) tons. 3. Subtract the corn field amount from the total amount: \[ \frac{127}{10} - \frac{61}{10} = \frac{127 - 61}{10} = \frac{66}{10}. \] 4. Simplify the fraction \( \frac{66}{10} \) by dividing both numerator and denominator by their greatest common divisor, which is 2: \[ \frac{66 \div 2}{10 \div 2} = \frac{33}{5}. \] 5. Optionally, convert the improper fraction to a mixed number: \[ \frac{33}{5} = 6 \frac{3}{5}. \] The farmer will have \( \frac{33}{5} \) tons, or \( 6 \frac{3}{5} \) tons, of fertilizer left for his other crops.