Question
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Find the derivative of the function \( h(x)=\left(6 x^{2}+7 x\right)^{5} \)

Ask by Alexander Wagner. in the United States
Feb 25,2025

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Answer

The derivative of \( h(x) = (6x² + 7x)^5 \) is \( h'(x) = 5(6x² + 7x)^4 (12x + 7) \).

Solution

To differentiate h(x) = (6x² + 7x)⁵, we use the chain rule. Identify the inner function and the outer function: • Let u(x) = 6x² + 7x (the inner function) • Then h(x) = [u(x)]⁵ (the outer function) Step 1. Differentiate the outer function with respect to u:   d/du [u⁵] = 5u⁴ Step 2. Differentiate the inner function u(x) with respect to x:   u'(x) = d/dx (6x² + 7x)      = 12x + 7 Step 3. Apply the chain rule:   h'(x) = 5[u(x)]⁴ · u'(x)      = 5(6x² + 7x)⁴ · (12x + 7) Thus, the derivative is:   h'(x) = 5(6x² + 7x)⁴ (12x + 7)

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To find the derivative of the function \( h(x) = (6x^2 + 7x)^5 \), we can use the chain rule. The chain rule states that if you have a composite function \( f(g(x)) \), the derivative is \( f'(g(x)) \cdot g'(x) \). In this case, let \( u = 6x^2 + 7x \), then \( h(x) = u^5 \). First, we find the derivative of \( u \): \[ u' = \frac{d}{dx}(6x^2 + 7x) = 12x + 7. \] Next, find the derivative of \( h \) with respect to \( u \): \[ h' = \frac{d}{du}(u^5) = 5u^4. \] Now, applying the chain rule: \[ h'(x) = h'(u) \cdot u' = 5u^4 \cdot (12x + 7). \] Substituting back \( u = 6x^2 + 7x \): \[ h'(x) = 5(6x^2 + 7x)^4 \cdot (12x + 7). \] Therefore, the derivative is: \[ h'(x) = 5(6x^2 + 7x)^4(12x + 7). \]

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