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II. Calcula los siguientes limites \( \begin{array}{ll}\text { 1. } \operatorname{Lim}_{x \rightarrow 2}\left(\frac{x^{3}+2 x+3}{x^{2}+5}\right) & \text { 6. } \operatorname{Lim}_{x \rightarrow 1}\left(\frac{4 x-1}{2 x^{2}-3 x+4}\right) \\ \text { 2. } \operatorname{Lim}_{x \rightarrow-1}\left(\frac{2 x+1}{x^{2}-3 x+4}\right) & \text { 7. } \operatorname{Lim}_{x \rightarrow 3}\left(\frac{3 x^{2}-1}{4 x^{2}+2}\right) \\ \text { 3. } \operatorname{Lim}_{x \rightarrow-3}\left(\frac{x^{2}-9}{2 x^{2}+7 x-3}\right) & \text { 8. } \lim _{x \rightarrow-5}\left(\frac{x^{3}-5}{3 x^{3}+x^{2}-5}\right) \\ \text { 4. } \operatorname{Lim}_{x \rightarrow 4}\left(\frac{x^{2}-4 x+1}{3 x^{2}-2 x+1}\right) & \text { 9. } \operatorname{Lim}_{x \rightarrow 0}\left(\frac{x^{3}-4 x^{2}+x-1}{2 x^{2}+4 x-1}\right) \\ \text { 5. } \operatorname{Lim}_{x \rightarrow 0}\left(\frac{x^{2}-3 x}{x+1}\right) & \end{array} \)

Ask by Gardner Murray. in Colombia
Mar 18,2025

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Answer

Aquí están los resultados de los límites: 1. \( \lim_{x \rightarrow 2}\left(\frac{x^{3}+2 x+3}{x^{2}+5}\right) = \frac{5}{3} \) 2. \( \lim_{x \rightarrow -1}\left(\frac{2 x+1}{x^{2}-3 x+4}\right) = -\frac{1}{8} \) 3. \( \lim_{x \rightarrow -3}\left(\frac{x^{2}-9}{2 x^{2}+7 x-3}\right) = 0 \) 4. \( \lim_{x \rightarrow 4}\left(\frac{x^{2}-4 x+1}{3 x^{2}-2 x+1}\right) = \frac{1}{41} \) 5. \( \lim_{x \rightarrow 0}\left(\frac{x^{2}-3 x}{x+1}\right) = 0 \) 6. \( \lim_{x \rightarrow 1}\left(\frac{4 x-1}{2 x^{2}-3 x+4}\right) = 1 \) 7. \( \lim_{x \rightarrow 3}\left(\frac{3 x^{2}-1}{4 x^{2}+2}\right) = \frac{13}{19} \) 8. \( \lim_{x \rightarrow -5}\left(\frac{x^{3}-5}{3 x^{3}+x^{2}-5}\right) = \frac{26}{71} \) 9. \( \lim_{x \rightarrow 0}\left(\frac{x^{3}-4 x^{2}+x-1}{2 x^{2}+4 x-1}\right) = 1 \) Si necesitas más detalles sobre algún cálculo específico, házmelo saber.

Solution

Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 4}\left(\frac{x^{2}-4x+1}{3x^{2}-2x+1}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 4}\left(x^{2}-4x+1\right)}{\lim _{x\rightarrow 4}\left(3x^{2}-2x+1\right)}\) - step2: Calculate: \(\frac{1}{\lim _{x\rightarrow 4}\left(3x^{2}-2x+1\right)}\) - step3: Calculate: \(\frac{1}{41}\) Calculate the limit \( \lim_{x \rightarrow 1}\left(\frac{4 x-1}{2 x^{2}-3 x+4}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 1}\left(\frac{4x-1}{2x^{2}-3x+4}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 1}\left(4x-1\right)}{\lim _{x\rightarrow 1}\left(2x^{2}-3x+4\right)}\) - step2: Calculate: \(\frac{3}{\lim _{x\rightarrow 1}\left(2x^{2}-3x+4\right)}\) - step3: Calculate: \(\frac{3}{3}\) - step4: Calculate: \(1\) Calculate the limit \( \lim_{x \rightarrow 3}\left(\frac{3 x^{2}-1}{4 x^{2}+2}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 3}\left(\frac{3x^{2}-1}{4x^{2}+2}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 3}\left(3x^{2}-1\right)}{\lim _{x\rightarrow 3}\left(4x^{2}+2\right)}\) - step2: Calculate: \(\frac{26}{\lim _{x\rightarrow 3}\left(4x^{2}+2\right)}\) - step3: Calculate: \(\frac{26}{38}\) - step4: Calculate: \(\frac{13}{19}\) Calculate the limit \( \lim_{x \rightarrow 0}\left(\frac{x^{3}-4 x^{2}+x-1}{2 x^{2}+4 x-1}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 0}\left(\frac{x^{3}-4x^{2}+x-1}{2x^{2}+4x-1}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 0}\left(x^{3}-4x^{2}+x-1\right)}{\lim _{x\rightarrow 0}\left(2x^{2}+4x-1\right)}\) - step2: Calculate: \(\frac{-1}{\lim _{x\rightarrow 0}\left(2x^{2}+4x-1\right)}\) - step3: Calculate: \(\frac{-1}{-1}\) - step4: Calculate: \(1\) Calculate the limit \( \lim_{x \rightarrow -1}\left(\frac{2 x+1}{x^{2}-3 x+4}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow -1}\left(\frac{2x+1}{x^{2}-3x+4}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow -1}\left(2x+1\right)}{\lim _{x\rightarrow -1}\left(x^{2}-3x+4\right)}\) - step2: Calculate: \(\frac{-1}{\lim _{x\rightarrow -1}\left(x^{2}-3x+4\right)}\) - step3: Calculate: \(\frac{-1}{8}\) - step4: Calculate: \(-\frac{1}{8}\) Calculate the limit \( \lim_{x \rightarrow 2}\left(\frac{x^{3}+2 x+3}{x^{2}+5}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 2}\left(\frac{x^{3}+2x+3}{x^{2}+5}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 2}\left(x^{3}+2x+3\right)}{\lim _{x\rightarrow 2}\left(x^{2}+5\right)}\) - step2: Calculate: \(\frac{15}{\lim _{x\rightarrow 2}\left(x^{2}+5\right)}\) - step3: Calculate: \(\frac{15}{9}\) - step4: Calculate: \(\frac{5}{3}\) Calculate the limit \( \lim_{x \rightarrow -5}\left(\frac{x^{3}-5}{3 x^{3}+x^{2}-5}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow -5}\left(\frac{x^{3}-5}{3x^{3}+x^{2}-5}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow -5}\left(x^{3}-5\right)}{\lim _{x\rightarrow -5}\left(3x^{3}+x^{2}-5\right)}\) - step2: Calculate: \(\frac{-130}{\lim _{x\rightarrow -5}\left(3x^{3}+x^{2}-5\right)}\) - step3: Calculate: \(\frac{-130}{-355}\) - step4: Calculate: \(\frac{26}{71}\) Calculate the limit \( \lim_{x \rightarrow 0}\left(\frac{x^{2}-3 x}{x+1}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow 0}\left(\frac{x^{2}-3x}{x+1}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow 0}\left(x^{2}-3x\right)}{\lim _{x\rightarrow 0}\left(x+1\right)}\) - step2: Calculate: \(\frac{0}{\lim _{x\rightarrow 0}\left(x+1\right)}\) - step3: Calculate: \(\frac{0}{1}\) - step4: Calculate: \(0\) Calculate the limit \( \lim_{x \rightarrow -3}\left(\frac{x^{2}-9}{2 x^{2}+7 x-3}\right) \). Evaluate the limit by following steps: - step0: Evaluate the limit: \(\lim _{x\rightarrow -3}\left(\frac{x^{2}-9}{2x^{2}+7x-3}\right)\) - step1: Rewrite the expression: \(\frac{\lim _{x\rightarrow -3}\left(x^{2}-9\right)}{\lim _{x\rightarrow -3}\left(2x^{2}+7x-3\right)}\) - step2: Calculate: \(\frac{0}{\lim _{x\rightarrow -3}\left(2x^{2}+7x-3\right)}\) - step3: Calculate: \(\frac{0}{-6}\) - step4: Calculate: \(0\) Aquí están los límites calculados: 1. \( \lim_{x \rightarrow 2}\left(\frac{x^{3}+2 x+3}{x^{2}+5}\right) = \frac{5}{3} \) 2. \( \lim_{x \rightarrow -1}\left(\frac{2 x+1}{x^{2}-3 x+4}\right) = -\frac{1}{8} \) 3. \( \lim_{x \rightarrow -3}\left(\frac{x^{2}-9}{2 x^{2}+7 x-3}\right) = 0 \) 4. \( \lim_{x \rightarrow 4}\left(\frac{x^{2}-4 x+1}{3 x^{2}-2 x+1}\right) = \frac{1}{41} \) 5. \( \lim_{x \rightarrow 0}\left(\frac{x^{2}-3 x}{x+1}\right) = 0 \) 6. \( \lim_{x \rightarrow 1}\left(\frac{4 x-1}{2 x^{2}-3 x+4}\right) = 1 \) 7. \( \lim_{x \rightarrow 3}\left(\frac{3 x^{2}-1}{4 x^{2}+2}\right) = \frac{13}{19} \) 8. \( \lim_{x \rightarrow -5}\left(\frac{x^{3}-5}{3 x^{3}+x^{2}-5}\right) = \frac{26}{71} \) 9. \( \lim_{x \rightarrow 0}\left(\frac{x^{3}-4 x^{2}+x-1}{2 x^{2}+4 x-1}\right) = 1 \) Si necesitas más detalles sobre algún cálculo específico, házmelo saber.

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The Deep Dive

Aquí tienes los límites de las funciones que mencionaste: 1. \(\operatorname{Lim}_{x \rightarrow 2}\left(\frac{x^{3}+2 x+3}{x^{2}+5}\right) = \frac{2^3 + 2(2) + 3}{2^2 + 5} = \frac{8 + 4 + 3}{4 + 5} = \frac{15}{9} = \frac{5}{3}\) 2. \(\operatorname{Lim}_{x \rightarrow -1}\left(\frac{2 x+1}{x^{2}-3 x+4}\right) = \frac{2(-1)+1}{(-1)^{2} -3(-1) + 4} = \frac{-2+1}{1 + 3 + 4} = \frac{-1}{8}\) 3. \(\operatorname{Lim}_{x \rightarrow -3}\left(\frac{x^{2}-9}{2 x^{2}+7 x-3}\right) = \frac{(-3)^{2}-9}{2(-3)^{2}+7(-3)-3} = \frac{9-9}{18-21-3} = \frac{0}{-6} = 0\) 4. \(\operatorname{Lim}_{x \rightarrow 4}\left(\frac{x^{2}-4 x+1}{3 x^{2}-2 x+1}\right) = \frac{4^{2}-4(4)+1}{3(4)^{2}-2(4)+1} = \frac{16 - 16 + 1}{48 - 8 + 1} = \frac{1}{41}\) 5. \(\operatorname{Lim}_{x \rightarrow 0}\left(\frac{x^{2}-3 x}{x+1}\right) = \frac{0^{2}-3(0)}{0+1} = \frac{0}{1} = 0\) 6. \(\operatorname{Lim}_{x \rightarrow 1}\left(\frac{4 x-1}{2 x^{2}-3 x+4}\right) = \frac{4(1)-1}{2(1)^{2}-3(1)+4} = \frac{4-1}{2-3+4} = \frac{3}{3} = 1\) 7. \(\operatorname{Lim}_{x \rightarrow 3}\left(\frac{3 x^{2}-1}{4 x^{2}+2}\right) = \frac{3(3)^{2}-1}{4(3)^{2}+2} = \frac{27-1}{36+2} = \frac{26}{38} = \frac{13}{19}\) 8. \(\lim _{x \rightarrow-5}\left(\frac{x^{3}-5}{3 x^{3}+x^{2}-5}\right) = \frac{(-5)^{3}-5}{3(-5)^{3}+(-5)^{2}-5} = \frac{-125-5}{-375+25-5} = \frac{-130}{-355} = \frac{130}{355} = \frac{26}{71}\) 9. \(\operatorname{Lim}_{x \rightarrow 0}\left(\frac{x^{3}-4 x^{2}+x-1}{2 x^{2}+4 x-1}\right) = \frac{0^{3}-4(0)^{2}+0-1}{2(0)^{2}+4(0)-1} = \frac{-1}{-1} = 1\) Puedes usar estos resultados para seguir practicando límites y mejorar tus habilidades en cálculo. ¡Diviértete!

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