Question
A pile of cards contains eight cards, numbered 1 through 8 . What is the probability of NOT choosing the 6 ? \( \frac{8}{7} \) \( \frac{1}{7} \) \( \frac{1}{8} \) ( (
Ask by Harrington Mcdonald. in the United States
Mar 01,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
The probability of not choosing the 6 is \( \frac{7}{8} \).
Solution
There are 8 cards in total and only one of them is numbered 6. The probability of selecting a card that is not the 6 is the number of non-6 cards divided by the total number of cards:
Prob(not choosing 6) = 7/8
So the correct answer is 7/8.
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Simplify this solution Beyond the Answer
To find the probability of not choosing the 6, we first determine the total number of possible outcomes, which is 8 (the total cards). If we don't want to choose the 6, there are 7 favorable outcomes (all cards except the 6). Therefore, the probability of not choosing the 6 is the number of favorable outcomes divided by the total outcomes, so it's \( \frac{7}{8} \). Now, when dealing with simple probability problems, a common mistake is to forget to account for all outcomes or to misinterpret what is being asked (like confusing choosing with not choosing). Always double-check if your answer aligns with the situation at hand!
