A pile of cards contains eight cards, numbered 1 through 8 . What is the probability of NOT choosing the 6 ? \( \frac{8}{7} \) \( \frac{1}{7} \) \( \frac{1}{8} \) ( (

To find the probability of not choosing the 6, we first determine the total number of possible outcomes, which is 8 (the total cards). If we don't want to choose the 6, there are 7 favorable outcomes (all cards except the 6). Therefore, the probability of not choosing the 6 is the number of favorable outcomes divided by the total outcomes, so it's \( \frac{7}{8} \). Now, when dealing with simple probability problems, a common mistake is to forget to account for all outcomes or to misinterpret what is being asked (like confusing choosing with not choosing). Always double-check if your answer aligns with the situation at hand!