Question
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Tara's chemistry textbook weighs \( 3 / 4 \) of a pound and her geometry textbook weighs \( 1 / 8 \) of a pound. How much more does the chemistry textbook weigh than the geometry textbook? Write your answer as a fraction or as a whole or mixed number. pounds

Ask by Ortiz Martin. in the United States
Feb 25,2025

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Tutor-Verified Answer

Answer

The chemistry textbook weighs \( \frac{5}{8} \) pounds more than the geometry textbook.

Solution

Calculate or simplify the expression \( 3/4 - 1/8 \). Calculate the value by following steps: - step0: Calculate: \(\frac{3}{4}-\frac{1}{8}\) - step1: Reduce fractions to a common denominator: \(\frac{3\times 2}{4\times 2}-\frac{1}{8}\) - step2: Multiply the numbers: \(\frac{3\times 2}{8}-\frac{1}{8}\) - step3: Transform the expression: \(\frac{3\times 2-1}{8}\) - step4: Multiply the numbers: \(\frac{6-1}{8}\) - step5: Subtract the numbers: \(\frac{5}{8}\) The chemistry textbook weighs \( \frac{5}{8} \) pounds more than the geometry textbook.

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Beyond the Answer

To find out how much more the chemistry textbook weighs than the geometry textbook, we need to subtract the weight of the geometry textbook from the weight of the chemistry textbook. First, let's convert both weights to have a common denominator. The weight of the chemistry textbook is \( \frac{3}{4} \) and the geometry textbook is \( \frac{1}{8} \). The common denominator of 4 and 8 is 8. Now we convert \( \frac{3}{4} \): \[ \frac{3}{4} = \frac{3 \times 2}{4 \times 2} = \frac{6}{8} \] Now we can subtract: \[ \frac{6}{8} - \frac{1}{8} = \frac{5}{8} \] Therefore, the chemistry textbook weighs \( \frac{5}{8} \) pounds more than the geometry textbook. \(\frac{5}{8}\) pounds

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