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To solve the equation \( 6t^{2} + 7t + 2 = 0 \), we can use the quadratic formula: \[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 6 \), \( b = 7 \), and \( c = 2 \). **Step 1**: Calculate the discriminant \( b^2 - 4ac \). \[ b^2 - 4ac = 7^2 - 4 \cdot 6 \cdot 2 = 49 - 48 = 1 \] **Step 2**: Use the quadratic formula. \[ t = \frac{-7 \pm \sqrt{1}}{2 \cdot 6} = \frac{-7 \pm 1}{12} \] **Step 3**: Calculate the two possible values for \( t \). 1. \( t = \frac{-7 + 1}{12} = \frac{-6}{12} = -\frac{1}{2} \) 2. \( t = \frac{-7 - 1}{12} = \frac{-8}{12} = -\frac{2}{3} \) Thus, the solutions for \( t \) are \[ t = -\frac{1}{2} \quad \text{and} \quad t = -\frac{2}{3} \]