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Solve for \( t \) \[ 6 t^{2}+7 t+2=0 \]

Ask by Hobbs Alexander. in the United States
Mar 09,2025

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Tutor-Verified Answer

Answer

\( t = -\frac{1}{2} \) or \( t = -\frac{2}{3} \).

Solution

We start with the equation \[ 6t^2 + 7t + 2 = 0. \] **Step 1: Identify the coefficients** The quadratic equation has the standard form \[ at^2 + bt + c = 0, \] with \[ a = 6, \quad b = 7, \quad c = 2. \] **Step 2: Compute the discriminant** The discriminant is given by \[ \Delta = b^2 - 4ac. \] Substitute the values: \[ \Delta = 7^2 - 4 \cdot 6 \cdot 2 = 49 - 48 = 1. \] **Step 3: Apply the quadratic formula** The quadratic formula is \[ t = \frac{-b \pm \sqrt{\Delta}}{2a}. \] Substitute the values: \[ t = \frac{-7 \pm \sqrt{1}}{2 \cdot 6} = \frac{-7 \pm 1}{12}. \] **Step 4: Find the two solutions** 1. For the positive square root: \[ t = \frac{-7 + 1}{12} = \frac{-6}{12} = -\frac{1}{2}. \] 2. For the negative square root: \[ t = \frac{-7 - 1}{12} = \frac{-8}{12} = -\frac{2}{3}. \] **Final Answer:** \[ t = -\frac{1}{2} \quad \text{or} \quad t = -\frac{2}{3}. \]

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To solve the equation \( 6t^{2} + 7t + 2 = 0 \), we can use the quadratic formula: \[ t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] Here, \( a = 6 \), \( b = 7 \), and \( c = 2 \). **Step 1**: Calculate the discriminant \( b^2 - 4ac \). \[ b^2 - 4ac = 7^2 - 4 \cdot 6 \cdot 2 = 49 - 48 = 1 \] **Step 2**: Use the quadratic formula. \[ t = \frac{-7 \pm \sqrt{1}}{2 \cdot 6} = \frac{-7 \pm 1}{12} \] **Step 3**: Calculate the two possible values for \( t \). 1. \( t = \frac{-7 + 1}{12} = \frac{-6}{12} = -\frac{1}{2} \) 2. \( t = \frac{-7 - 1}{12} = \frac{-8}{12} = -\frac{2}{3} \) Thus, the solutions for \( t \) are \[ t = -\frac{1}{2} \quad \text{and} \quad t = -\frac{2}{3} \]

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