8. The bonds present in \( \mathrm{N}_{2} \mathrm{O}_{4} \) are \( \begin{array}{ll}\text { (a) Only ionic } & \text { (b) Only covalent } \\ \text { (c) Covalent and coordinate } & \text { (d) Ionic and coordinate }\end{array} \)

To determine the type of bonds present in \( \mathrm{N}_{2} \mathrm{O}_{4} \), we need to consider the nature of the atoms involved and the type of bonding that occurs between them. \( \mathrm{N}_{2} \mathrm{O}_{4} \) consists of nitrogen (N) and oxygen (O) atoms. Nitrogen is a nonmetal, and oxygen is a nonmetal as well. When nonmetals bond together, they typically form covalent bonds. In \( \mathrm{N}_{2} \mathrm{O}_{4} \), the nitrogen atoms are bonded to each other through a covalent bond, and each nitrogen atom is also bonded to four oxygen atoms through covalent bonds. This indicates that the bonds present in \( \mathrm{N}_{2} \mathrm{O}_{4} \) are covalent. Therefore, the correct answer is: (b) Only covalent