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\( \begin{array}{ll}\text { a) } 8 x+5 x & \text { б) } x+21 \cdot x+10 \quad x\end{array} \)

Ask by Carrillo Ramos. in Turkmenistan
Mar 12,2025

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a) \( 13x \) б) \( 32x \)

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First, let's add the terms in the first expression: \(8x + 5x\) simplifies to \(13x\). You combine the coefficients (8 and 5) because they are like terms. For the second expression, we distribute the terms: \(x + 21 \cdot x + 10x\) simplifies to \(x + 21x + 10x = 32x\). Here, we distribute \(x\) in front of \(21x\) and \(10x\), ultimately leading to a total of \(32x\).

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