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Evaluate the expression for \( q=-13, r=5 \), and \( s=0 \). Simplify your answer. \( \frac{s^{2}}{r s+q}=\square \)

Ask by Montgomery Montgomery. in the United States
Jan 12,2025

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Answer

The expression simplifies to 0.

Solution

To evaluate the expression \( \frac{s^{2}}{r s + q} \) with the given values \( q = -13 \), \( r = 5 \), and \( s = 0 \), follow these steps: 1. **Substitute the values into the expression:** \[ \frac{0^{2}}{5 \times 0 + (-13)} \] 2. **Calculate the numerator:** \[ 0^{2} = 0 \] 3. **Calculate the denominator:** \[ 5 \times 0 + (-13) = 0 - 13 = -13 \] 4. **Simplify the expression:** \[ \frac{0}{-13} = 0 \] So, the simplified value of the expression is: \[ 0 \]

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To evaluate the expression \( \frac{s^{2}}{r s+q} \) with \( q = -13 \), \( r = 5 \), and \( s = 0 \), we first substitute these values into the expression. Calculating the numerator: \[ s^{2} = 0^{2} = 0 \] Now for the denominator: \[ rs + q = 5 \cdot 0 + (-13) = 0 - 13 = -13 \] Putting it all together: \[ \frac{s^{2}}{rs + q} = \frac{0}{-13} = 0 \] Thus, the simplified answer is: \[ 0 \]

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