What is the future value after 12 years if you deposit \( \$ 1,000 \) for your child's education and the interest is guaranteed at \( 1.9 \% \) compounded continuously? (Round your answer to the nearest cent.) \( \$ \)
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The Deep Dive
To find the future value \( FV \) of an investment compounded continuously, you can use the formula: \[ FV = P \times e^{rt} \] where: - \( P \) is the principal amount (initial deposit), - \( r \) is the interest rate (as a decimal), - \( t \) is the time in years, - \( e \) is the base of the natural logarithm (approximately equal to 2.71828). In this case: - \( P = 1000 \) - \( r = 0.019 \) (1.9% as a decimal) - \( t = 12 \) Plugging in the values: \[ FV = 1000 \times e^{0.019 \times 12} \] Calculating \( e^{0.019 \times 12} \): \[ FV = 1000 \times e^{0.228} \] Now, calculating \( e^{0.228} \) gives approximately 1.256. Now, calculate the future value: \[ FV = 1000 \times 1.256 \approx 1256.63 \] So, the future value after 12 years will be approximately: \[ \boxed{1256.63} \]