Factor the numerator and denominator. Do not simplify the common factors. \[ \frac{x^{2}+7 x+6}{x^{2}+3 x-18}=\square \]

To factor the numerator \(x^{2}+7x+6\), we look for two numbers that multiply to 6 (the constant term) and add up to 7 (the coefficient of \(x\)). These numbers are 1 and 6. Thus, the numerator factors as \((x + 1)(x + 6)\). Next, we factor the denominator \(x^{2}+3x-18\). Here, we need two numbers that multiply to -18 and add to 3. Those numbers are 6 and -3, leading us to factor the denominator as \((x + 6)(x - 3)\). So, the expression without simplifying the common factors is: \[ \frac{(x + 1)(x + 6)}{(x + 6)(x - 3)} = \square \]