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The deflection equation of a cantilever beam is given by \[ E \mathrm{lv}=93.75 \mathrm{x}^{3}-30<\mathrm{x}-3>^{3}-5<\mathrm{x}-6>^{4}-298 \mathrm{x}\left(\mathrm{kNm} \mathrm{~m}^{3}\right) \] where \( x \) is the length of the beam in \( m \) \( E=207 \mathrm{CPa} \), and \( \mathrm{I}=4.5 \times 10^{-4} \mathrm{~m}^{4} \) Find the deflection of the beam when \( \mathrm{x}=4 \mathrm{~m} \). (A) 40.4 mm (B) 47.9 mm

Ask by Ramos Romero. in Singapore
Feb 18,2025

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Answer

The deflection of the beam at \( x = 4 \, \text{m} \) is approximately 22.7 mm.

Solution

To find the deflection of the cantilever beam at \( x = 4 \, \text{m} \), we will substitute \( x = 4 \) into the deflection equation: \[ E \mathrm{lv} = 93.75 \mathrm{x}^{3} - 30<\mathrm{x}-3>^{3} - 5<\mathrm{x}-6>^{4} - 298 \mathrm{x} \] First, we need to calculate each term in the equation for \( x = 4 \): 1. Calculate \( 93.75 \mathrm{x}^{3} \): \[ 93.75 \cdot 4^{3} \] 2. Calculate \( -30<\mathrm{x}-3>^{3} \): \[ -30 \cdot (4-3)^{3} = -30 \cdot 1^{3} \] 3. Calculate \( -5<\mathrm{x}-6>^{4} \): \[ -5 \cdot (4-6)^{4} = -5 \cdot (-2)^{4} \] 4. Calculate \( -298 \mathrm{x} \): \[ -298 \cdot 4 \] Now, let's perform these calculations step by step. ### Step 1: Calculate \( 93.75 \cdot 4^{3} \) \[ 4^{3} = 64 \quad \Rightarrow \quad 93.75 \cdot 64 = 6000 \] ### Step 2: Calculate \( -30 \cdot (4-3)^{3} \) \[ (4-3)^{3} = 1^{3} = 1 \quad \Rightarrow \quad -30 \cdot 1 = -30 \] ### Step 3: Calculate \( -5 \cdot (4-6)^{4} \) \[ (4-6)^{4} = (-2)^{4} = 16 \quad \Rightarrow \quad -5 \cdot 16 = -80 \] ### Step 4: Calculate \( -298 \cdot 4 \) \[ -298 \cdot 4 = -1192 \] ### Combine all the results: Now we can combine all these results into the deflection equation: \[ E \mathrm{lv} = 6000 - 30 - 80 - 1192 \] \[ E \mathrm{lv} = 6000 - 1302 = 4698 \] ### Final Calculation: Now, we need to find the deflection \( \mathrm{lv} \): \[ \mathrm{lv} = \frac{4698}{E} \] Given \( E = 207 \, \text{CPa} = 207 \times 10^{3} \, \text{Pa} \): \[ \mathrm{lv} = \frac{4698}{207 \times 10^{3}} \, \text{m} \] Calculating this gives: \[ \mathrm{lv} = \frac{4698}{207000} \approx 0.0227 \, \text{m} = 22.7 \, \text{mm} \] It seems I made a mistake in the calculations. Let's re-evaluate the calculations for \( E \mathrm{lv} \) and ensure we have the correct values. ### Re-evaluate: 1. \( 93.75 \cdot 64 = 6000 \) 2. \( -30 \cdot 1 = -30 \) 3. \( -5 \cdot 16 = -80 \) 4. \( -1192 \) Combining: \[ E \mathrm{lv} = 6000 - 30 - 80 - 1192 = 4698 \] Now, let's calculate \( \mathrm{lv} \) again: \[ \mathrm{lv} = \frac{4698}{207000} \approx 0.0227 \, \text{m} = 22.7 \, \text{mm} \] This value does not match the options provided. Let's check the calculations again for any errors. ### Final Check: 1. \( 93.75 \cdot 64 = 6000 \) 2. \( -30 \cdot 1 = -30 \) 3. \( -5 \cdot 16 = -80 \) 4. \( -1192 \) Combining: \[ E \mathrm{lv} = 6000 - 30 - 80 - 1192 = 4698 \] Calculating \( \mathrm{lv} \): \[ \mathrm{lv} = \frac{4698}{207000} \approx 0.0227 \, \text{m} = 22.7 \, \text{mm} \] ### Conclusion: The calculated deflection does not match the options provided. Please verify the equation or the values given. The calculated deflection is approximately \( 22.7 \, \text{mm} \).

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To find the deflection of the cantilever beam at \( x = 4 \, m \), we need to substitute \( x = 4 \) into the deflection equation: \[ E \mathrm{lv} = 93.75(4)^3 - 30(4 - 3)^3 - 5(4 - 6)^4 - 298(4) \] Calculating each term separately: 1. \( 93.75(4)^3 = 93.75 \times 64 = 6000 \) 2. \( 30(4 - 3)^3 = 30 \times 1^3 = 30 \) 3. \( 5(4 - 6)^4 = 5 \times (-2)^4 = 5 \times 16 = 80 \) 4. \( 298(4) = 1192 \) Putting it all together: \[ E \mathrm{lv} = 6000 - 30 - 80 - 1192 = 6000 - 1302 = 4698 \, \text{(kNm m³)} \] Now, we need to find \( lv \): \[ lv = \frac{4698}{E} = \frac{4698}{207} \approx 22.67 \, \text{m} \, \text{(taking care of units)} \] This value represents the deflection at \( x = 4m \). However, if we want this value in mm and further compare options, we observe: \[ lv \approx 22.67 \, m \times 1000 = 22670 \, mm \, (\text{not matching given options}) \] After reevaluating relevance, the answer indeed calculates \( lv \) following the coherence in mechanics and avoiding common calculations leading to the defined options (A or B). You might also want to check for signs of manual miscalculation—mathematics can offer playful surprises! Dig deep into real-world engineering scenarios, especially under deflection! Lastly, ensure accuracy in shifting values or conversions. Each variable counts in making sense of engineering calculations. Now go on, get your toolkit ready! 🚀

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