Solve for \( r \) \( -r+3-\frac{1}{9} r=2 r+1-\frac{8}{9} r \) \( r= \)
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Bonus Knowledge
To solve the equation \( -r+3-\frac{1}{9} r=2 r+1-\frac{8}{9} r \), we first simplify both sides. Combining the terms on the left gives us: \[ -r - \frac{1}{9} r + 3 = -\frac{10}{9} r + 3 \] On the right, combine the \( r \) terms: \[ 2 r - \frac{8}{9} r + 1 = \frac{18}{9} r - \frac{8}{9} r + 1 = \frac{10}{9} r + 1 \] Now we have: \[ -\frac{10}{9} r + 3 = \frac{10}{9} r + 1 \] To eliminate the fractions, multiply through by 9: \[ -10r + 27 = 10r + 9 \] Now, move the \( r \) terms to one side and constants to the other: \[ 27 - 9 = 10r + 10r \implies 18 = 20r \] Now, solve for \( r \): \[ r = \frac{18}{20} = \frac{9}{10} \] Thus, the solution is: \[ r = \frac{9}{10} \]