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Mo had 2 goals in one game out of 6 shots attempted. a. Find the experimental probability Mo will shoot a goal when attem b. Mo has 9 attempts in a game. Predict how many goals he scores. Let \( x= \) number of

Ask by Potter Macdonald. in the United States
Feb 26,2025

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a. The probability that Mo will score a goal on any shot is 1/3. b. Mo is predicted to score 3 goals in 9 attempts.

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Mo's experimental probability of scoring a goal is calculated by dividing the number of goals by the number of attempts. So, for 2 goals out of 6 shots, the probability is:   Probability = 2/6 = 1/3 ≈ 0.33 a. The experimental probability that Mo will score a goal on any shot is 1/3. b. Using this probability, if Mo takes 9 shots in a game, the predicted number of goals is found by multiplying the probability by the number of attempts:   Predicted goals = (1/3) × 9 = 3 Thus, if Mo has 9 attempts, he is predicted to score 3 goals.

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Mo's experimental probability of scoring a goal is calculated by taking the number of successful goals (2) and dividing it by the total attempts (6). So, the probability \( P \) is \( P = \frac{2}{6} = \frac{1}{3} \). This means that Mo has about a 33.3% chance of scoring with each shot he attempts. If we apply this probability to his next game with 9 attempts, we can predict his goals by multiplying his shooting probability by the number of attempts: \( x = 9 \times \frac{1}{3} \). This means Mo is expected to score about 3 goals in his next game!

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