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- \( 84 x=21 x^{2} \)

Ask by Moreno Wagner. in Mexico
Feb 25,2025

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Tutor-Verified Answer

Answer

Las soluciones son \( x = 0 \) y \( x = 4 \).

Solution

Para resolver la ecuación \( 84x = 21x^2 \), seguimos estos pasos: 1. **Reorganizar la ecuación**: Primero, llevamos todos los términos a un lado de la ecuación para igualarla a cero. Esto se hace restando \( 84x \) de ambos lados: \[ 21x^2 - 84x = 0 \] 2. **Factorizar la ecuación**: Ahora, podemos factorizar la ecuación. Observamos que ambos términos tienen un factor común de \( 21x \): \[ 21x(x - 4) = 0 \] 3. **Encontrar las soluciones**: Para que el producto sea cero, al menos uno de los factores debe ser cero. Por lo tanto, tenemos dos casos: - \( 21x = 0 \) - \( x - 4 = 0 \) Resolviendo cada caso: - Para \( 21x = 0 \): \[ x = 0 \] - Para \( x - 4 = 0 \): \[ x = 4 \] 4. **Conclusión**: Las soluciones de la ecuación \( 84x = 21x^2 \) son: \[ x = 0 \quad \text{y} \quad x = 4 \]

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Beyond the Answer

To solve the equation \( 84x = 21x^2 \), start by rearranging it to one side: \( 21x^2 - 84x = 0 \). Factor out the common term \( 21x \), leading to \( 21x(x - 4) = 0 \). This gives two solutions: \( x = 0 \) or \( x = 4 \). So, we find that the solutions are \( x = 0 \) and \( x = 4 \). An interesting twist in mathematics is that equations like this can have many applications, from physics to economics. For instance, in physics, such equations might represent relationships between quantities, like force and area, which can help solve real-world problems, such as calculating pressure. However, when solving quadratic equations, a common mistake is to forget to check for all possible solutions, especially in cases where factoring may lead to extraneous solutions. Make sure to substitute your answers back into the original equation to confirm they are valid solutions!

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