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\( \left. \begin{array} { l l } { 16 = 4 ^ { 2 } } \\ { 8 ^ { - 2 } = \frac { 1 } { 64 } } & { 0 = \log _ { 6 } 1 } \\ { \log _ { x } x ^ { 4 } = 4 } \\ { m ^ { n } = P } & { \log _ { 6 } ( \frac { 1 } { 36 } ) = - 2 } \\ { 3 ^ { 0 } = 1 } & { 2 = \log _ { \frac { 1 } { 4 } } x } \\ { \frac { 1 } { 5 \times - 3 } = 0,001 } & { } \end{array} \right. \)

Ask by Willis Malone. in South Africa
Feb 20,2025

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Answer

The true statements are: - \( 16 = 4^2 \) - \( 8^{-2} = \frac{1}{64} \) - \( 0 = \log_6 1 \) - \( \log_x x^4 = 4 \) - \( \log_6 \left( \frac{1}{36} \right) = -2 \) - \( 3^0 = 1 \) - \( 2 = \log_{\frac{1}{4}} x \) (where \( x = \frac{1}{16} \)) The false statement is: - \( \frac{1}{5 \times -3} = 0.001 \)

Solution

Let's analyze the given equations step by step. 1. **Equation 1:** \( 16 = 4^2 \) - This is a true statement since \( 4^2 = 16 \). 2. **Equation 2:** \( 8^{-2} = \frac{1}{64} \) - We can rewrite \( 8^{-2} \) as \( \frac{1}{8^2} \). - Since \( 8^2 = 64 \), we have \( 8^{-2} = \frac{1}{64} \), which is also true. 3. **Equation 3:** \( 0 = \log_6 1 \) - The logarithm of 1 in any base is 0, so this statement is true. 4. **Equation 4:** \( \log_x x^4 = 4 \) - Using the property of logarithms, we can rewrite this as \( 4 \cdot \log_x x = 4 \). - Since \( \log_x x = 1 \), we have \( 4 \cdot 1 = 4 \), which is true. 5. **Equation 5:** \( m^n = P \) - This is a general exponential equation and does not provide specific values. 6. **Equation 6:** \( \log_6 \left( \frac{1}{36} \right) = -2 \) - We can rewrite \( \frac{1}{36} \) as \( 6^{-2} \). - Therefore, \( \log_6 (6^{-2}) = -2 \), which is true. 7. **Equation 7:** \( 3^0 = 1 \) - This is a true statement since any non-zero number raised to the power of 0 is 1. 8. **Equation 8:** \( 2 = \log_{\frac{1}{4}} x \) - We can rewrite this as \( x = \left( \frac{1}{4} \right)^2 \). - Since \( \left( \frac{1}{4} \right)^2 = \frac{1}{16} \), we have \( x = \frac{1}{16} \). 9. **Equation 9:** \( \frac{1}{5 \times -3} = 0.001 \) - Calculating the left side: \( 5 \times -3 = -15 \), so \( \frac{1}{-15} \) is approximately -0.0667, which is not equal to 0.001. This statement is false. In summary, the true statements are: - \( 16 = 4^2 \) - \( 8^{-2} = \frac{1}{64} \) - \( 0 = \log_6 1 \) - \( \log_x x^4 = 4 \) - \( \log_6 \left( \frac{1}{36} \right) = -2 \) - \( 3^0 = 1 \) - \( 2 = \log_{\frac{1}{4}} x \) (where \( x = \frac{1}{16} \)) The false statement is: - \( \frac{1}{5 \times -3} = 0.001 \)

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The Deep Dive

Did you know that logarithms were invented to make complex calculations simpler, acting like a bridge between multiplication and addition? The concept of logarithms dates back to the early 17th century, when mathematician John Napier introduced them. Imagine trying to solve a large multiplication problem without repeated addition—the logarithm was a game-changer in the world of mathematics, paving the way for advances in science and engineering! In everyday life, you might encounter logarithmic relationships in aspects like sound intensity measured in decibels or the Richter scale for earthquakes. This means when you feel the ground shake, scientists can describe its strength with a logarithmic scale. So, next time you hear about a magnitude 7 quake, remember it's not just a number—it's a logarithmic description of how much more intense it is than a magnitude 6!

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