Question
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Use the compound interest formula to compute the total amount accumulated and the interest eamed. \( \$ 4500 \) for 3 years at \( 8 \% \) compounded quarterly The total amount accumulated after 3 years is \( \$ \square \). (Round to the nearest cent as needed.)

Ask by Peterson Collins. in the United States
Mar 09,2025

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Answer

The total amount accumulated after 3 years is $5,707.09, and the interest earned is $1,207.09.

Solution

To calculate the total amount accumulated and the interest earned using the compound interest formula, we can use the formula: \[ A = P \left( 1 + \frac{r}{n} \right)^{nt} \] where: - \( A \) is the total amount accumulated - \( P \) is the principal amount (initial amount) - \( r \) is the annual interest rate (in decimal form) - \( n \) is the number of times the interest is compounded per year - \( t \) is the time in years Given: - Principal amount (\( P \)) = $4500 - Annual interest rate (\( r \)) = 8% = 0.08 - Compounded quarterly, so \( n = 4 \) - Time (\( t \)) = 3 years Substitute the given values into the formula: \[ A = 4500 \left( 1 + \frac{0.08}{4} \right)^{4 \times 3} \] Now, we can calculate the total amount accumulated after 3 years. Calculate the value by following steps: - step0: Calculate: \(4500\left(1+\frac{0.08}{4}\right)^{4\times 3}\) - step1: Divide the terms: \(4500\left(1+\frac{1}{50}\right)^{4\times 3}\) - step2: Add the numbers: \(4500\left(\frac{51}{50}\right)^{4\times 3}\) - step3: Multiply the numbers: \(4500\left(\frac{51}{50}\right)^{12}\) - step4: Simplify: \(4500\times \frac{51^{12}}{50^{12}}\) - step5: Rewrite the expression: \(50\times 90\times \frac{51^{12}}{50^{12}}\) - step6: Reduce the numbers: \(90\times \frac{51^{12}}{50^{11}}\) - step7: Rewrite the expression: \(10\times 9\times \frac{51^{12}}{50^{11}}\) - step8: Rewrite the expression: \(10\times 9\times \frac{51^{12}}{10^{11}\times 5^{11}}\) - step9: Reduce the numbers: \(9\times \frac{51^{12}}{10^{10}\times 5^{11}}\) - step10: Multiply the fractions: \(\frac{9\times 51^{12}}{10^{10}\times 5^{11}}\) The total amount accumulated after 3 years is approximately $5707.09. To find the interest earned, we can subtract the principal amount from the total amount accumulated: Interest earned = Total amount accumulated - Principal amount Interest earned = $5707.09 - $4500 Interest earned = $1207.09 Therefore, the interest earned after 3 years is $1207.09.

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To find the total amount accumulated with the compound interest formula, we can use: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( P = 4500 \) (the principal amount), - \( r = 0.08 \) (the annual interest rate), - \( n = 4 \) (the number of times interest is compounded per year), - \( t = 3 \) (the number of years). Plugging in the values: \[ A = 4500 \left(1 + \frac{0.08}{4}\right)^{4 \times 3} \] \[ A = 4500 \left(1 + 0.02\right)^{12} \] \[ A = 4500 \left(1.02\right)^{12} \] Calculating \( (1.02)^{12} \) gives approximately \( 1.268241795 \). Now calculate \( A \): \[ A \approx 4500 \times 1.268241795 \approx 5716.09 \] So the total amount accumulated after 3 years is \( \$ 5716.09 \). To find the interest earned, subtract the principal from the total amount: \[ \text{Interest} = A - P = 5716.09 - 4500 = 1216.09 \] So, the interest earned is \( \$ 1216.09 \).

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