Use the compound interest formula to compute the total amount accumulated and the interest eamed. \( \$ 4500 \) for 3 years at \( 8 \% \) compounded quarterly The total amount accumulated after 3 years is \( \$ \square \). (Round to the nearest cent as needed.)
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To find the total amount accumulated with the compound interest formula, we can use: \[ A = P \left(1 + \frac{r}{n}\right)^{nt} \] where: - \( P = 4500 \) (the principal amount), - \( r = 0.08 \) (the annual interest rate), - \( n = 4 \) (the number of times interest is compounded per year), - \( t = 3 \) (the number of years). Plugging in the values: \[ A = 4500 \left(1 + \frac{0.08}{4}\right)^{4 \times 3} \] \[ A = 4500 \left(1 + 0.02\right)^{12} \] \[ A = 4500 \left(1.02\right)^{12} \] Calculating \( (1.02)^{12} \) gives approximately \( 1.268241795 \). Now calculate \( A \): \[ A \approx 4500 \times 1.268241795 \approx 5716.09 \] So the total amount accumulated after 3 years is \( \$ 5716.09 \). To find the interest earned, subtract the principal from the total amount: \[ \text{Interest} = A - P = 5716.09 - 4500 = 1216.09 \] So, the interest earned is \( \$ 1216.09 \).
