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\( \frac{3}{8} x-2=\frac{1}{8}(3 x-16) \) one solution no solution infinitely many solutions two solutions

Ask by Chadwick Bob. in the United States
Nov 21,2024

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The equation has infinitely many solutions.

Solution

Solve the equation \( \frac{3}{8}x-2=\frac{1}{8}(3x-16) \). Solve the equation by following steps: - step0: Solve for \(x\): \(\frac{3}{8}x-2=\frac{1}{8}\left(3x-16\right)\) - step1: Multiply the terms: \(\frac{3}{8}x-2=\frac{3}{8}x-2\) - step2: The statement is true: \(x \in \mathbb{R}\) The equation \( \frac{3}{8}x-2=\frac{1}{8}(3x-16) \) has infinitely many solutions. Therefore, the correct answer is "infinitely many solutions".

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To solve the equation \( \frac{3}{8} x - 2 = \frac{1}{8}(3 x - 16) \), start by simplifying both sides. Distributing on the right side gives \( \frac{3}{8} x - 2 = \frac{3}{8} x - 2 \). When you bring all terms to one side, you get \( 0 = 0 \). This means every value of \( x \) satisfies the equation, leading us to conclude that there are infinitely many solutions! It’s a neat aspect of algebra that sometimes, instead of finding a single solution or a conflict, you can discover that an equation is true for all possible values of the variable. This happens when the two sides of the equation are identical after simplification—an algebraic harmony!

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