\( A=\frac{h(x+10)}{2} \) \( A=27 \) \( h=4 \) Workont the calue of \( x \)
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To find the value of \( x \), we start with the equation \( A = \frac{h(x + 10)}{2} \). We know that \( A = 27 \) and \( h = 4 \). Substituting the known values into the equation, we have: \[ 27 = \frac{4(x + 10)}{2} \] Simplifying the right side, we get: \[ 27 = \frac{4}{2}(x + 10) \implies 27 = 2(x + 10) \] Next, divide both sides by 2: \[ \frac{27}{2} = x + 10 \] \[ 13.5 = x + 10 \] Now, solving for \( x \): \[ x = 13.5 - 10 \implies x = 3.5 \] So, the value of \( x \) is \( 3.5 \).